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Re: st: RE: Creating a new variable via another variable name based on a condition


From   Eric Booth <ebooth@ppri.tamu.edu>
To   "<statalist@hsphsun2.harvard.edu>" <statalist@hsphsun2.harvard.edu>
Subject   Re: st: RE: Creating a new variable via another variable name based on a condition
Date   Thu, 8 Jul 2010 20:17:32 +0000

<>

I also reshaped to long but approached it a different (and longer way) than Nick.

********!
clear
inp firms hrs_owner1 hrs_owner2 hrs_owner3 equity_owner1 equity_owner2 equity_owner3 
1 3  2  0 50  25 25 
2 2  3  6 25  50 25 
3 3  8  . 75  25 . 
4 2  .  2 80  . 20 
end
**reshape**
reshape long hrs_owner equity_owner, i(firms) j(ownerid)
**find max**
	bys firms: egen maxhours = max(hrs_owner)
**find ties**
	g main_owner = ownerid if maxhours==hrs_owner
	bys firms: egen maxequity = max(equity_owner) if !mi(main_owner)
**replace main_owner with tied owner with most equity**
	bys firms: replace main_owner = . if maxequity != equity_owner
	bys firms (main_owner): replace main_owner = main_owner[1]
	drop max*
********!

but I got a different answer than when I use Nick's solution (translated into my varnames):

bysort firms (hrs_ equity_) : gen main = ownerid[_N] 

If I've translated the varnames correctly, I think Nick's command can assign main ownership to ids with missing data.  There might be a better way to fix Nick's solution, but one way looks to be to recode the missings to zero:

********
recode hrs_ equity_ (.=0)
bysort firms (hrs_ equity_) : gen main = ownerid[_N] 
recode hrs_ equity_ (0=.)
********
	
~ Eric
__
Eric A. Booth
Public Policy Research Institute
Texas A&M University
ebooth@ppri.tamu.edu

On Jul 8, 2010, at 2:46 PM, Nick Cox wrote:

> (You should -update- to 8.2. It's free.) 
> 
> You should -reshape- your data to -long-. Then no loops are required. 
> 
> You don't give variable names. I will assume 
> 
> Firm identifier: id 
> Hours worked by owners 1, 2, etc.: hours1, etc. 
> Equity owned by owners 1, 2, etc.: equity1, etc. 
> 
> The -reshape- is 
> 
> reshape long hours equity, i(id) 
> 
> Then 
> 
> rename _j owner
> mvencode *, mv(0) override
> bysort id (hours equity) : gen main = owner[_N]
> 
> Repeat: no loops. 
> 
> Nick 
> n.j.cox@durham.ac.uk 
> 
> Indu Khurana
> 
> Creating a new variable via another variable name based on a condition
> 
> Using stata 8.0. I am trying to create a logical condition which would
> copy the name of the variable if satisfied.
> 
> Here is what I have:
> 
> Aim is to identify the main owner. I have generated one variable Main
> Owner
> I assign value to this variable using maximum no. of hours worked.
> 
> I have information on
> 1. Total 10 owners. Sometimes there may be only 1 or 2 owners.
> 2. Hours - Number of hours worked per week.
> 3. Equity - Equity ownership by each worker.
> I have data for 5 years. There are approximately 5000 firms.
> 
> There are 2 issues:
> 1. Lets say there are 2 owners (1 and 2) . Owner1 works for 3 hours
> and Owner2 works for 2 hours, then I want the variable main owner to
> take the value 1. How can I post the name of the variable and not the
> value?
> 2. Now if the hours worked for the owners are the same I use Equity
> ownership as the variable to resolve the tie. In that case owner with
> maximum equity ownership becomes the main owner. How to create a loop
> for this?
> 
> 1st year data
> 
> 
> Firms Hrs owner1 Hrs owner2  Hrs owner3  main owner
> 1             3                2               0                  1
> 2              2               3              6                   3
> 3              3               8               .                   2
> 4              2                .              2         tie - go to
> equity
> .
> .
> .
> 5000
> 
> Firms Equity ownr1  Equity ownr2  Equity owner3  main ownr
> 1                50                25                      25         1
> 2                25                50                      25         3
> 3                75                25                       .          2
> 4                80                 .                       20         1
> .
> .
> .
> 5000
> 
> 
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