Thanks Nick. I forgot to mention that I tried with and without spaces,
because the error appears in any case.
. gen rn = rnormal(0,9)
Unknown function rnormal()
r(133);
2009/3/19 Nick Cox <[email protected]>:
> This is not a matter covered by an FAQ because it's just a matter of standard syntax as explained in the help and the manuals.
>
> Think about it from Stata's point of view. Only if you write -rnormal()- with no space -- and arguments supplied within () -- does it know that you want a function with that name. There is no rule against a variable called -rnormal-, so your reference to -rnormal- followed by a space indicates to Stata that you mean to refer to a variable with that name. You don't have one, so it throws you out in a state of puzzlement with a message that is perfectly reasonable.
>
> set obs 100
> gen rn = rnormal(0,9)
>
> Nick
> [email protected]
>
> Rodrigo Briceño
>
> I would like to know if there is a function similar to this that I
> found in R: norm <- rnorm(100, 2, 5)
> The trick is to generate a variable that contains 100 values with are
> normal distributed with mean 2 and stdev 5.
>
> I found that rnormal is a function in Stata, but I am not sure about
> the way to write the sintax to produce that outcome. I tried with:
> generate rn=rnormal (0,9) but a message telling me rnormal is not
> found appeared.
>
> I looked into FAQ but there are no related issues...
>
> *
> * For searches and help try:
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> * http://www.stata.com/support/statalist/faq
> * http://www.ats.ucla.edu/stat/stata/
>
--
Rodrigo Briceño
Economist
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