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Re: st: RE: Return r(111) this time


From   jjc.li@utoronto.ca
To   statalist@hsphsun2.harvard.edu
Subject   Re: st: RE: Return r(111) this time
Date   Sun, 15 Mar 2009 17:18:29 -0400

Here's the return:


. matrix a = J(1,62,0)

. set trace on

.
. nlsurwellbehav "copies of dep. variables" "right hand side variables" , at(a) ---------------------------------------------------------------- begin nlsurwellbehav ---
- version 10.1
- syntax varlist(min=16 max=16) [if], at(name)
time-series operators not allowed
------------------------------------------------------------------ end nlsurwellbehav ---
r(101);

Jingjing





Quoting Eva Poen <eva.poen@gmail.com>:

Jingjing,

I'm not sure I understand you here. Are you referring to the line

replace `lnc' = 5+`aq'*`lnq' ...

where there is a hard coded 5 (not a starting value! This is a set
value.), and did you replace this value of 5 by another parameter,
e.g. `a0'? In terms of the program, that is not a problem as long as
you adjust your code. It would be easiest if you put this parameter
last, since this saves you the pain of changing all your `at'[1,x]
statements to `at'[1,x+1]. Therefore, my suggestion would be to code

       scalar `dmm'=`at'[1,61]
       tempname a0
       scalar `a0'    =`at'[1,62]


       quietly {
          replace `lnc' = `a0'+ ....
       }

Now, for the debugging, just follow my suggestions earlier, and invoke
your program directly. You need to create a matrix of initial values,
e.g. zeros for all coefficients. If you have 62 parameters, you do

matrix a = J(1,62,0)

which gives you a row vector of 62 zeros. Next create copies of all
your dependent variables, and invoke your program:

set trace on
nlsurwellbehav "copies of dep. variables" "right hand side variables" , at(a)

and see where the problem lies.

Eva


2009/3/15  <jjc.li@utoronto.ca>:
Hi,

First, I corrected all the typo.

Then I changed constant item 5 to a0 in the first equation. I setted
constant item a0 as a strating value 5 in my previous codes, because they
did so in the example. Now I decide to scalar a new coef. a0. Is that ok? Or
I need to set the constant item at other starting value?

Second, I typed -set trace on- before running the stuff. Here's the error
record:


}
-------------------------------------------------------------- end
nlsurwellbehav  ---
- }
- if _rc {
- di as error "nlsur`eqn' returned " _rc
= di as error "nlsurwellbehav returned " _rc
nlsurwellbehav returned 111
- di as error "verify that nlsur`eqn' is a function evaluator program"
= di as error "verify that nlsurwellbehav is a function evaluator program"
verify that nlsurwellbehav is a function evaluator program
- exit _rc
}
}
---------------------------------------------------------------- end
nlsur.Estimate  ---
end nlsur       ---
r(111);

I am thinking there maybe another kind of errors in my codes. Say there's
two items in my equation:   a*lne   and   b*lne*lne. I think I should define
them as:

replace `lnc'=`a'*`lne'+`b'*``lnpe'*`lne''

In my previous codes I defined them as:

`lnc'=`a'*`lne'+`b'*`lnpe'*`lne'

Does it cause the r(111)?

Jingjing


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