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Re: st: RE: Return r(111) this time

From   [email protected]
To   [email protected]
Subject   Re: st: RE: Return r(111) this time
Date   Sun, 15 Mar 2009 17:21:13 -0400 
My data combine 4 regions together with dummy variables as following

sm	se	t	d1	d2
.6592281	.027027	1	1	0
.7192982	.0263158	2	1	0
.7461538	.0230769	3	1	0
.7723577	.0243902	4	1	0
.7862595	.0229008	5	1	0
.8114285	.0171429	6	1	0
.8058823	.0176471	7	1	0
.8171428	.0171429	8	1	0
.7743902	.0182927	9	1	0
.7607362	.0245399	10	1	0
.755102	.0272109	11	1	0
.7569444	.0208333	12	1	0
.7588652	.0212766	13	1	0
.7536232	.0217391	14	1	0
.736	.024	15	1	0
.725	.0333333	16	1	0
.7629629	.0222222	17	1	0
.760274	.0273973	18	1	0
.5359314	.0367697	1	0	1
.5833333	.0357143	2	0	1
.62	.04	3	0	1
.6037736	.0377358	4	0	1
.6962963	.0222222	5	0	1
.6805556	.0208333	6	0	1
.7375	.01875	7	0	1
.7484277	.0188679	8	0	1
.7465754	.0205479	9	0	1
.7191781	.0273973	10	0	1
.7142857	.0225564	11	0	1
.7152778	.0208333	12	0	1
.7092199	.0212766	13	0	1
.6953125	.03125	14	0	1
.7177419	.0322581	15	0	1
.7213115	.0327869	16	0	1
.7122302	.0215827	17	0	1
.7103449	.0275862	18	0	1
.6496138	.041598	1	0	0
.7070707	.040404	2	0	0
.6952381	.047619	3	0	0
.7102804	.0373832	4	0	0
.7272727	.0363636	5	0	0
.7438017	.0330578	6	0	0
.7537314	.0298507	7	0	0
.7569444	.0347222	8	0	0
.7357143	.0357143	9	0	0
.76	.0266667	10	0	0
.78125	.025	11	0	0
.7449664	.0268456	12	0	0
.7375886	.035461	13	0	0
.7142857	.037594	14	0	0
.7251908	.0305344	15	0	0
.7209302	.0310078	16	0	0
.7307692	.0384615	17	0	0
.7132353	.0367647	18	0	0
.6315789	.0345543	1	0	0
.6315789	.037594	2	0	0
.6258993	.0431655	3	0	0
.6090226	.0451128	4	0	0
.620438	.0437956	5	0	0
.610687	.0458015	6	0	0
.6736111	.0416667	7	0	0
.6394558	.0408163	8	0	0
.6470588	.0392157	9	0	0
.6547619	.0357143	10	0	0
.6566265	.0361446	11	0	0
.6526946	.0299401	12	0	0
.6521739	.0310559	13	0	0
.6325301	.0361446	14	0	0
.6369048	.0416667	15	0	0
.6453488	.0406977	16	0	0
.6436782	.045977	17	0	0
.6436782	.045977	18	0	0
.6698113	.0260135	1	0	0
.6698113	.0283019	2	0	0
.6697248	.0275229	3	0	0
.6666667	.0285714	4	0	0
.6315789	.0263158	5	0	0
.6694915	.0254237	6	0	0
.716129	.0258065	7	0	0
.7356322	.0344828	8	0	0
.7368421	.0233918	9	0	0
.7431694	.0218579	10	0	0
.7235294	.0235294	11	0	0
.70625	.025	12	0	0
.7142857	.0310559	13	0	0
.7586207	.0413793	14	0	0
.6923077	.027972	15	0	0
.6766917	.037594	16	0	0
.6842105	.037594	17	0	0
.7007299	.0437956	18	0	0
.6422764	.0373636	1	0	0
.6422764	.0406504	2	0	0
.6446281	.0495868	3	0	0
.6341463	.0487805	4	0	0
.632	.04	5	0	0
.6532258	.0322581	6	0	0
.6814815	.0296296	7	0	0
.6595744	.0283688	8	0	0
.6758621	.0206897	9	0	0
.7012987	.025974	10	0	0
.7019867	.0198676	11	0	0
.6973684	.0263158	12	0	0
.69375	.025	13	0	0
.7065868	.0239521	14	0	0
.7025316	.0316456	15	0	0
.7168674	.0301205	16	0	0
.7142857	.0357143	17	0	0
.718232	.0220994	18	0	0
.6666667	.0167117	1	0	0
.6666667	.0181818	2	0	0
.6666667	.0175439	3	0	0
.671875	.015625	4	0	0
.6836734	.0204082	5	0	0
.7040817	.0204082	6	0	0
.733945	.0183486	7	0	0
.75	.015873	8	0	0
.7572464	.0144928	9	0	0
.7695035	.0177305	10	0	0
.7676057	.0176056	11	0	0
.7822878	.0184502	12	0	0
.7814815	.0185185	13	0	0
.755814	.0232558	14	0	0
.756	.02	15	0	0
.7448559	.0246914	16	0	0
.6525822	.028169	17	0	0
.6359649	.0263158	18	0	0



Does the time variable cause the problem?

Jingjing


Quoting Eva Poen <[email protected]>:


Jingjing,

I'm not sure I understand you here. Are you referring to the line


replace `lnc' = 5+`aq'*`lnq' ...


where there is a hard coded 5 (not a starting value! This is a set
value.), and did you replace this value of 5 by another parameter,
e.g. `a0'? In terms of the program, that is not a problem as long as
you adjust your code. It would be easiest if you put this parameter
last, since this saves you the pain of changing all your `at'[1,x]
statements to `at'[1,x+1]. Therefore, my suggestion would be to code

       scalar `dmm'=`at'[1,61]
       tempname a0
       scalar `a0'    =`at'[1,62]


       quietly {
          replace `lnc' = `a0'+ ....
       }

Now, for the debugging, just follow my suggestions earlier, and invoke
your program directly. You need to create a matrix of initial values,
e.g. zeros for all coefficients. If you have 62 parameters, you do

matrix a = J(1,62,0)

which gives you a row vector of 62 zeros. Next create copies of all
your dependent variables, and invoke your program:

set trace on
nlsurwellbehav "copies of dep. variables" "right hand side variables" , at(a)

and see where the problem lies.

Eva


2009/3/15  <[email protected]>:

Hi,

First, I corrected all the typo.

Then I changed constant item 5 to a0 in the first equation. I setted
constant item a0 as a strating value 5 in my previous codes, because they
did so in the example. Now I decide to scalar a new coef. a0. Is that ok? Or
I need to set the constant item at other starting value?

Second, I typed -set trace on- before running the stuff. Here's the error
record:


}
-------------------------------------------------------------- end
nlsurwellbehav  ---
- }
- if _rc {
- di as error "nlsur`eqn' returned " _rc
= di as error "nlsurwellbehav returned " _rc
nlsurwellbehav returned 111
- di as error "verify that nlsur`eqn' is a function evaluator program"
= di as error "verify that nlsurwellbehav is a function evaluator program"
verify that nlsurwellbehav is a function evaluator program
- exit _rc
}
}
---------------------------------------------------------------- end
nlsur.Estimate  ---
end nlsur       ---
r(111);

I am thinking there maybe another kind of errors in my codes. Say there's
two items in my equation:   a*lne   and   b*lne*lne. I think I should define
them as:

replace `lnc'=`a'*`lne'+`b'*``lnpe'*`lne''

In my previous codes I defined them as:

`lnc'=`a'*`lne'+`b'*`lnpe'*`lne'

Does it cause the r(111)?

Jingjing



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