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Re: st: RE: forval question again


From   Rike <silvery.enigma@gmail.com>
To   statalist@hsphsun2.harvard.edu
Subject   Re: st: RE: forval question again
Date   Wed, 11 Feb 2009 13:26:25 -0500

Howie's idea worked. Thanks everyone.

On 2/11/09, Howard Lempel <HLempel@brookings.edu> wrote:
> This is probably not the most concise code.  That being said, try:
>
> local start = start_year[1]
> local end = end_year[1]
>
> forval `start'/`end' {
> 	do stuff
> 	}
>
> Hope this helps.
> Howie
>
>
>
> -----Original Message-----
> From: owner-statalist@hsphsun2.harvard.edu
> [mailto:owner-statalist@hsphsun2.harvard.edu] On Behalf Of Rike
> Sent: Wednesday, February 11, 2009 1:06 PM
> To: statalist
> Subject: st: forval question again
>
> Dear all,
>
> this is a follow up question on the one right below.
>
> I have tried
>
>  forval x = start_year[1]/end_year[1] {
>
>  }
>
>
> but it gives me the invalid syntax error.
>
> As for using r(min) and r(max) as per Martin's suggestion, I don't
> think it will work because start_year and end_year are two different
> variables. Any other ideas? Here is my question again:
>
> I want forval to loop over the (min) value of two variables. More
> specifically, there is a variable called start_year and another called
> end_year and what I want is something like this:
>
> forval x = start_year / end_year  {
> .
> .
> }
>
> The variables have all the same value but i want to repeat the same
> codes across different samples that have varying starting and ending
> years. This is why I don't want to put the years in numbers as this
> would create a lot more work.
>
> Is there a way to do this?
>
> Thanks in advance.
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