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Re: st: RE: Create categorical variable based on 'z-score'


From   George Hoffman <ghoffman@mcw.edu>
To   <statalist@hsphsun2.harvard.edu>
Subject   Re: st: RE: Create categorical variable based on 'z-score'
Date   Wed, 26 Nov 2008 16:18:24 -0600

Wonderful economy. Thanks.
gh


> From: Nick Cox <n.j.cox@durham.ac.uk>
> Reply-To: <statalist@hsphsun2.harvard.edu>
> Date: Wed, 26 Nov 2008 20:58:49 +0000
> To: <statalist@hsphsun2.harvard.edu>
> Subject: RE: st: RE: Create categorical variable based on 'z-score'
> 
> You want to round up when positive, down when negative.
> 
> egen z = std(foo)
> replace z = cond(z == 0, 0, cond(z > 0, ceil(z), floor(z)))
> 
> Nick 
> n.j.cox@durham.ac.uk
> 
> George Hoffman
> 
> Thanks, nick. Egen std works. Can I nest floor(ceil(x)) to get the
> desired
> ...?
> 
> Nick Cox <n.j.cox@durham.ac.uk>
>  
>> Despite various answers, no one mention -egen, std()- followed by
>> -floor()- and -ceil(). All existing official Stata.
> 
> George Hoffman
>  
>> Generic problem: I'd like to create categorical variables for a list
> of
>> continuous variables. The categorical variables would be based upon
> the
>> z-score of each variable, such as:
>> Z-score of X     catX
>> <-2             -3
>> -2 ..-1         -2
>> -1 .. 0         -1
>> 0               0
>> 0.. +1          +1
>> 1 ..2           +2
>>> +2             +3
>> 
>> If there were a way to z-transform variables, I could do an easy
>> recode(catX)
> 
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