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From |
<Alexander.Severinsen@telenor.com> |

To |
<statalist@hsphsun2.harvard.edu> |

Subject |
st: SV: RE: SV: RE: Time of day |

Date |
Thu, 28 Aug 2008 15:04:33 +0200 |

I did not realize I could use -split- to solve this. Thanks for the pointer! Best wishes, Alexander Severinsen -----Opprinnelig melding----- Fra: owner-statalist@hsphsun2.harvard.edu [mailto:owner-statalist@hsphsun2.harvard.edu] På vegne av Nick Cox Sendt: 28. august 2008 14:42 Til: statalist@hsphsun2.harvard.edu Emne: st: RE: SV: RE: Time of day That gives you a string. You could in turn feed that to -ntimeofday-. As the help for -ntimeofday- indicates, -split- is often useful in this territory. Nick n.j.cox@durham.ac.uk Alexander.Severinsen@telenor.com Thanks for clarifying that for me. I got what a asked for, but I guess I did not ask the correct question. I had a date (string) like 11.02.2008 08:21:00.000, and wanted a new variable with only the time recorded, 08:21. I am looking at offer response (from telemarketing), and in this particular case the actual date is of no interest. After posting, I solved the problem using 'substr', not sure if that is the most efficient way, but, gen time=substr(result_date,12,13) list time in 1/2 +--------------+ | time | |--------------| 1. | 08:21:00.000 | 2. | 07:55:00.000 | +--------------+ gave me what I wanted. Nick Cox I tried hard to forget the minor agonies of writing -?timeofday- once StataCorp had done the job properly in Stata 10. But times in hours from -ntimeofday- are (as with all Stata date-times) measured relative to 1 January 1960. Some simple calculations show that hours above about 400000 are what you should get for recent dates. For example, today's date gives . di 24 * mdy(8,28,2008) 426528 So, my impression is that you got what you asked for, i.e. the result _is_ in hours. I wrote the -?timeofday- stuff because (a) some colleagues needed it (b) StataCorp did not seem inclined to do it. (b) was promptly reversed, but a consequence of (a) is that I have not used the official time of day stuff myself in Stata 10. But I would be surprised if you cannot get what you want using official commands. Nick n.j.cox@durham.ac.uk Alexander.Severinsen I use Stata 10. I have a string variable, result_date, that records day, month, year, hours, minutes, seconds. It displays, 11.02.2008 08:21:00.000 I would like to generate a new variable that only indicates hours. I had a look at the ntimeofday, written by Nicholas J. Cox (findit ntimeofday), and issed the following command, ntimeofday result_date, gen(ndatetime) s(dmy h mi s) n(h) It runs ok, but listing some of these values gives me list ndatetime in 1/2 | ndatetime | |-----------| 1. | 421760.35 | 2. | 421759.92 | I am not sure whether I am on the right track, and maybe all I am missing is to translate these numbers into hours? Any help would be greatly appreciated. * * For searches and help try: * http://www.stata.com/help.cgi?search * http://www.stata.com/support/statalist/faq * http://www.ats.ucla.edu/stat/stata/ * * For searches and help try: * http://www.stata.com/help.cgi?search * http://www.stata.com/support/statalist/faq * http://www.ats.ucla.edu/stat/stata/

**References**:**st: Time of day***From:*<Alexander.Severinsen@telenor.com>

**st: RE: Time of day***From:*"Nick Cox" <n.j.cox@durham.ac.uk>

**st: SV: RE: Time of day***From:*<Alexander.Severinsen@telenor.com>

**st: RE: SV: RE: Time of day***From:*"Nick Cox" <n.j.cox@durham.ac.uk>

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