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R: st: How to perform a productory (running product)

From   "Carlo Lazzaro" <>
To   <>
Subject   R: st: How to perform a productory (running product)
Date   Tue, 23 Oct 2007 09:13:09 +0200

Dear Nick, Josè Maria and Paulo (in order of appearance),

Thanks a lot for your contributions to the "Produttoria-Running Product-
Produtório Affair".

It seems quite funny how an efficient language such maths can show some
debateworthy differences in labelling the same procedure.

Thanks a lot again.

Kind Regards,


-----Messaggio originale-----
[] Per conto di josemaria
Inviato: lunedì 22 ottobre 2007 22.01
Oggetto: Re: st: How to perform a productory

For the sake of completeness:
Two Brazilian diccionaires for the Portuguese language registry the word 
"somatório". In statistics and mathematics we use the simbol upper-case 
Greek sigma. The same diccionaires do not registry "produtório", but we use 
it in the spoken language and the symbol is the upper-case Geek pi. Then, 
curiously, we have the symbol to write, the word to speak but not formally 
the writen word.
José Maria

José Maria Pacheco de Souza, Professor Titular (aposentado)
Departamento de Epidemiologia
Faculdade de Saúde Pública/Universidade de São Paulo
Av. Dr. Arnaldo, 715 cep 01246-904
São Paulo Brasil
fones   (11)3061-7747 (11)3061-7724 (11)3714-2403  (11)3768-8612
fax   (11)3082-2920  (11)3714-2403

----- Original Message ----- 
From: "Paulo Guimaraes" <>
To: <>
Sent: Monday, October 22, 2007 2:15 PM
Subject: Re: st: How to perform a productory

> In Portuguese (from Portugal) the word "produtório" is well known and 
> commonly used. It may be different in Brazil...
> Paulo Guimaraes
> josemaria wrote:
>> In Portuguese, we have somatório, same as soma (sum), but we do not have 
>> produtório.
>> José Maria
>>> I Googled "productory" and didn't find anything recognisable.
>>> Perhaps you want a running product.
>>> gen runningproduct = exp(sum(log(K_1)))
>>> Alternatively, if you ask in Italian, somebody should
>>> recognise what you want. There is no "English only" rule.
>>> Nick

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