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Re: st: efficient way to use local
From
Rebecca Pope <[email protected]>
To
[email protected]
Subject
Re: st: efficient way to use local
Date
Mon, 25 Feb 2013 12:14:41 -0600
I'm not sure this is "efficient", but you would need to use two
-forvalues- & you must close both sets of `'. Also, you must have ==
instead of = since you are asking Stata for a logical test.
forvalues i=1/2 {
forvalues j=1/2 {
regress il`i't `X`i'' if mon==`j'
}
}
(Code not tested)
This will run the regression il1t X1 for mon==1 and mon==2 and then
switch to il2t and X2.
Rebecca
On Mon, Feb 25, 2013 at 12:03 PM, Rodrigo Briceño <[email protected]> wrote:
> Dear Stata users. I am dealing with a dataset that has two slightly
> sets of explanatory and dependent variables. The sets are defined by
> having a 1 or 2 number inside their names and also a 1 or 2 number
> inside the values of one of the variables. My dependents are il1t and
> il2t. The values on the variable mon are 1 and 2. So in total my
> output is composed by 4 regressions (one for each 1 and 2t, and one
> for each mon value).
>
> I tried to do the following:
>
> local X1 "mc pmv1t dr1 dr2 dpl1t"
> local X2 "mc pmv2t dr1 dr2 dpl2t"
>
> forvalues i= 1 2{
>
> regress il`i't `X`i' if mon=`i'
> }
>
> but I got the error: invalid syntax r(198). I am not sure if you can
> use a local inside a local as I expressed on `X`i'
>
>
> Any help is fully appreciated.
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