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Re: st: How to replace a missing date with value?


From   Nick Cox <[email protected]>
To   [email protected]
Subject   Re: st: How to replace a missing date with value?
Date   Mon, 21 Jan 2013 17:01:24 +0000

There are two problems with your code.

1. Your first -replace- asks for a replacement of the date with the
-date()- equivalent of 29 February 2001. But 2001 was not a leap year,
so there was no 29 February that year, so Stata returns missing, and
nothing is changed.

2. Your second -replace- has exactly the same problem, plus the fact
that what you have supplied is not a DMY argument, but a MDY argument.

So, it seems likely that whatever leads you to apply 29 February is
wrong in this case.

Nick

On Mon, Jan 21, 2013 at 4:53 PM, Kanter, Rebecca <[email protected]> wrote:

> I am trying to replace date value that was missing (.) with the actual value that I now have.
>
> Given that date1 is a date (DMY) variable in %dM_d,_CY format..
>
> I do not understand why the below code does not result in the requested change to change date1==. (MISSING) to date1=29feb2001
>
> replace date1 = date("29-02-2001","DMY") in 23 (via edit)
> (0 real changes made)
>
>  replace date1 = date("02-29-2001","DMY") if  id=="12345" (via command screen)
> (0 real changes made)
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