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Re: st: Looping over variables

 From daniel klein To statalist@hsphsun2.harvard.edu Subject Re: st: Looping over variables Date Wed, 19 Dec 2012 11:31:46 +0100

```Ingeborg,

note that your changes to Nick's code are not necessary. The lines

replace n_preg = n_preg + inlist(aa`j', 1, 5) ///
| (inlist(aa`j', 2, 3, 4, 6, 7) & inrange(aa`J', 13, .))

Nick's code, and

replace n_preg = n_preg + 1 if inlist(aa`j', 1, 5) | ///
(inlist(aa`j', 2, 3, 4, 6, 7) & inrange(aa`J', 13, .))

return the same result. Note that Nick did (on purpose) not include an
-if- qualifier in front of the expression (in this case functions).
The expression

inlist(aa`j', 1, 5) ///
| (inlist(aa`j', 2, 3, 4, 6, 7) & inrange(aa`J', 13, .))

evaluates to 1 if it is true, 0 otherwise. So Stata adds 1 to n_preg
if the expression is true, 0 otherwise.

Nick's code is therefore just a convenient shortcut. It does not
matter in this example I believe, but be aware of missing values if
you wish to use this kind of shortcut, though.

Best
Daniel
--
Thank you very much for your advice!  It works! But as I want to count
the number of pregnancies for each observation (forgot to write this
in my first e-mail!) I had to add +1 in the third line in order for it
to add 1 for each pregnancy.

gen n_preg = 0

. forval j = 95(6)149 {
2.         local J = `j' + 1
3.         replace n_preg = n_preg + 1 if inlist(aa`j', 1, 5) |
(inlist(aa`j', 2, 3, 4, 6, 7) & inrange(aa`J', 13, .))
4. }

Ingeborg
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