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Re: st: how to generate a variable where one third of values would be randomly assigned
From
Nick Cox <[email protected]>
To
Nick Cox <[email protected]>
Subject
Re: st: how to generate a variable where one third of values would be randomly assigned
Date
Mon, 12 Dec 2011 15:59:56 +0000
-ceil()- should be -floor()-
On 12 Dec 2011, at 15:39, Nick Cox <[email protected]> wrote:
gen foo = cond(runiform() < 1/3, ceil(120 * runiform()), 120)
?
Nick
On 12 Dec 2011, at 15:04, Ekaterina Hertog <[email protected]
> wrote:
Dear all,
I use stata 11 and I need to generate a variable where two thirds
of observations (about 1300 obs) will be equal to 120 and the rest
of the values are randomly assigned, but are all integers and less
than 120.
Any advice will be very much appreciated,
Ekaterina
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