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Re: st: are Macro variable always possible ?


From   John Litfiba <cariboupad@gmx.fr>
To   statalist@hsphsun2.harvard.edu
Subject   Re: st: are Macro variable always possible ?
Date   Sun, 28 Aug 2011 20:56:41 +0200

Thank you very much Nick!

Best regards,


On 28 August 2011 20:47, Nick Cox <njcoxstata@gmail.com> wrote:
> Matthew is correct.
>
> If you try to -display- your macro by using " " you just get another
> version ot the same problem. There is an ambiguity between " as a
> string delimiter and " as a a literal character. You need to use
> compound double quotes again.
>
> . di `"`filter'"'
>
> By the way,
>
> . macro list
>
> gives a way of seeing macro definitions without encountering this problem.
>
> In Stata, macros are not considered to be variables and so the
> expression "macro variables" is best avoided. See e.g.
>
> http://www.stata.com/statalist/archive/2008-08/msg01258.html
>
> Nick
>
> On Sun, Aug 28, 2011 at 7:36 PM, John Litfiba <cariboupad@gmx.fr> wrote:
>> Hello Matt,
>>
>> Thank you very much for your kind answer
>> But... its doesnt seem to work, right ?
>>
>> If I call the macro I obtain the same error
>>
>> . display "`filter'"
>> var1==unknown function hello"&var2==1&var3==43&var6=="helloagain"&!missing()
>>
>>
>> On 28 August 2011 20:14, Matthew White <mwhite@poverty-action.org> wrote:
>>> Enclosing it in double quotes should do the trick:
>>> local filter `"var1=="hello"&var2==1&var3==43&var6=="hello
>>> again"&!missing(var34)"'
>>>
>>> Best,
>>> Matt
>>>
>>> On Sun, Aug 28, 2011 at 5:52 PM, John Litfiba <cariboupad@gmx.fr> wrote:
>>>> Dear Statalist,
>>>>
>>>> I have a very simple question about macro variables:
>>>>
>>>> I would like to define a macro variable which stores a long sequence
>>>> of data restrictions that I use after any IF qualifier when a function
>>>> allows it ..
>>>>
>>>> For example instead of writing
>>>>
>>>>  regress Y X if var1=="hello"&var2==1&var3==43&var6=="hello
>>>> again"&!missing(var34) ,
>>>>
>>>> I tried to define a macro as
>>>>
>>>>  local filter var1=="hello"&var2==1&var3==43&var6=="hello again"&!missing(var34)
>>>>
>>>> in order to simply write
>>>>
>>>> regress Y X if `filter'
>>>>
>>>> However it doent seem to work as Stata doesnt like at all the part
>>>> var1=="hello" (because of the ""), causing an error in the
>>>> interpretation...
>>>>
>>>> Has anyone an idea ?
>>>>
>
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