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Re: st: are Macro variable always possible ?
From
Nick Cox <[email protected]>
To
[email protected]
Subject
Re: st: are Macro variable always possible ?
Date
Sun, 28 Aug 2011 19:47:42 +0100
Matthew is correct.
If you try to -display- your macro by using " " you just get another
version ot the same problem. There is an ambiguity between " as a
string delimiter and " as a a literal character. You need to use
compound double quotes again.
. di `"`filter'"'
By the way,
. macro list
gives a way of seeing macro definitions without encountering this problem.
In Stata, macros are not considered to be variables and so the
expression "macro variables" is best avoided. See e.g.
http://www.stata.com/statalist/archive/2008-08/msg01258.html
Nick
On Sun, Aug 28, 2011 at 7:36 PM, John Litfiba <[email protected]> wrote:
> Hello Matt,
>
> Thank you very much for your kind answer
> But... its doesnt seem to work, right ?
>
> If I call the macro I obtain the same error
>
> . display "`filter'"
> var1==unknown function hello"&var2==1&var3==43&var6=="helloagain"&!missing()
>
>
> On 28 August 2011 20:14, Matthew White <[email protected]> wrote:
>> Enclosing it in double quotes should do the trick:
>> local filter `"var1=="hello"&var2==1&var3==43&var6=="hello
>> again"&!missing(var34)"'
>>
>> Best,
>> Matt
>>
>> On Sun, Aug 28, 2011 at 5:52 PM, John Litfiba <[email protected]> wrote:
>>> Dear Statalist,
>>>
>>> I have a very simple question about macro variables:
>>>
>>> I would like to define a macro variable which stores a long sequence
>>> of data restrictions that I use after any IF qualifier when a function
>>> allows it ..
>>>
>>> For example instead of writing
>>>
>>> regress Y X if var1=="hello"&var2==1&var3==43&var6=="hello
>>> again"&!missing(var34) ,
>>>
>>> I tried to define a macro as
>>>
>>> local filter var1=="hello"&var2==1&var3==43&var6=="hello again"&!missing(var34)
>>>
>>> in order to simply write
>>>
>>> regress Y X if `filter'
>>>
>>> However it doent seem to work as Stata doesnt like at all the part
>>> var1=="hello" (because of the ""), causing an error in the
>>> interpretation...
>>>
>>> Has anyone an idea ?
>>>
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