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From |
daniel klein <klein.daniel.81@googlemail.com> |

To |
statalist@hsphsun2.harvard.edu |

Subject |
Re: st: How to use functions within variable names |

Date |
Wed, 17 Aug 2011 10:09:16 +0200 |

Sdfsdfsadfsf , please note that it is practice on Statalist to use real names (c.f. http://www.stata.com/support/faqs/res/statalist.html#tojoin). Regarding your queston, there are two points to mention. 1. You will have to make sure that the expression you are using is evaluated "on the fly" while looping, as Maarten already has shown. Stata will evaluate forvalue i=1(1)100 { replace b_`i'= a[c+`i'] } to read forvalue i=1(1)100 { replace b_1= a[7+1] } the first time through the loop, meaning that Stata evaluates the local i but not the expression as a hole. To evaluate the expression you will need to code forvalue i=1(1)100 { loc expr = a + `i' replace b_`i'= a[`expr'] } or short forvalue i=1(1)100 { replace b_`i'= a[`= c+`i''] } 2. Note however, that c will always be evaluated to 7, or whichever value the first observation of c holds. You probably did not expect this behavior so you migth have to code something like this forvalue i=1(1)100 { replace b_`i'= a[`= c[`i'] + `i'] } It might be more convenient to use two parallel lists in the loop. Here (http://www.stata.com/support/faqs/lang/parallel.html) is how you do that. Given little information, I cannot comment on the appropriatness of your approach to solve the undelying problem. Best Daniel * * For searches and help try: * http://www.stata.com/help.cgi?search * http://www.stata.com/support/statalist/faq * http://www.ats.ucla.edu/stat/stata/

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