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From |
"Carlo Lazzaro" <carlo.lazzaro@tin.it> |

To |
<statalist@hsphsun2.harvard.edu> |

Subject |
st: R: % of people lying under a certain percentage of median income - (flag: Stata 9/2 SE) |

Date |
Sun, 3 Oct 2010 13:37:31 +0200 |

Dear Caterina, what follows can do the trick: --------- code begins--------------- set obs 100 g income=100000*uniform() qui sum income,d scalar A= r(N) count if income < .2*r(p50) di r(N)/A --------- code ends--------------- Kind Regards and Have a Nice Sunday, Carlo -----Messaggio originale----- Da: owner-statalist@hsphsun2.harvard.edu [mailto:owner-statalist@hsphsun2.harvard.edu] Per conto di Caterina Astarita Inviato: domenica 3 ottobre 2010 11.32 A: statalist-digest@hsphsun2.harvard.edu Oggetto: st: % of people lying under a certain percentage of median income Dear statalister, I would like to calculate the percentage of families having an income that lies below a certain percentage below the median income, let's say the 20% of the median income. Is there any command in Stata that performs this kind of calculus? Thank you Caterina * * For searches and help try: * http://www.stata.com/help.cgi?search * http://www.stata.com/support/statalist/faq * http://www.ats.ucla.edu/stat/stata/ * * For searches and help try: * http://www.stata.com/help.cgi?search * http://www.stata.com/support/statalist/faq * http://www.ats.ucla.edu/stat/stata/

**References**:**st: % of people lying under a certain percentage of median income***From:*Caterina Astarita <lasta01@students.bbk.ac.uk>

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