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Re: st: Question about scalars


From   Austin Nichols <austinnichols@gmail.com>
To   statalist@hsphsun2.harvard.edu
Subject   Re: st: Question about scalars
Date   Mon, 9 Aug 2010 15:51:32 -0400

Steve et al.:

d is an abbrev for displacement, and the first obs is 121.
Use scalar(d) instead.

On Mon, Aug 9, 2010 at 3:26 PM, Jeph Herrin <stata@spandrel.net> wrote:
> Yes, but look closely at
>
>> . scalar e = d + a
>> . scalar dir a d e // "e" is wrong
>>           a =         10
>>           d =  4.9458042
>>           e =        131
>
> You'll see that 4.94+10 = 131. Which is incorrect.
>
> cheers,
> Jeph
>
> On 8/9/2010 2:15 PM, Sergiy Radyakin wrote:
>>
>> Hi, Steve,
>>
>> there might be something else in your program that prevents it from
>> running. Both code fragments that you compare work fine in my Stata 9
>> and Stata 11.
>>
>> Best, Sergiy
>>
>> . do "R:\TEMP\STD0h000000.tmp"
>>
>> . clear
>>
>> . scalar drop _all
>>
>> . scalar a = 10
>>
>> . scalar b = 20
>>
>> . scalar c = b + a
>>
>> . scalar dir
>>          c =         30
>>          b =         20
>>          a =         10
>>
>> .
>> . sysuse auto, clear
>> (1978 Automobile Data)
>>
>> . reg mpg foreign
>>
>>       Source |       SS       df       MS              Number of obs =
>>  74
>> -------------+------------------------------           F(  1,    72) =
>> 13.18
>>        Model |  378.153515     1  378.153515           Prob>  F      =
>>  0.0005
>>     Residual |  2065.30594    72  28.6848048           R-squared     =
>>  0.1548
>> -------------+------------------------------           Adj R-squared =
>>  0.1430
>>        Total |  2443.45946    73  33.4720474           Root MSE      =
>>  5.3558
>>
>>
>> ------------------------------------------------------------------------------
>>          mpg |      Coef.   Std. Err.      t    P>|t|     [95% Conf.
>> Interval]
>>
>> -------------+----------------------------------------------------------------
>>      foreign |   4.945804   1.362162     3.63   0.001     2.230384
>>  7.661225
>>        _cons |   19.82692   .7427186    26.70   0.000     18.34634
>>  21.30751
>>
>> ------------------------------------------------------------------------------
>>
>> . scalar d = _b[foreign]
>>
>> . scalar e = d + a
>>
>> . scalar dir a d e // "e" is wrong
>>          a =         10
>>          d =  4.9458042
>>          e =        131
>>
>> .
>> . tempname dd
>>
>> . scalar `dd' = _b[foreign]
>>
>> . scalar e = `dd' +a
>>
>> . scalar dir a `dd' e // "e" is /okay
>>          a =         10
>>   __000000 =  4.9458042
>>          e =  14.945804
>>
>> .
>> end of do-file
>>
>>
>> On Mon, Aug 9, 2010 at 1:57 PM, Steve Samuels<sjsamuels@gmail.com>  wrote:
>>>
>>> In the code below, I generate a scalar "d" from a regression result;
>>> it looks okay, but trying to add it to another scalar doesn't work.
>>> If, however I use a -tempname- , I get the right answer.  Could
>>> someone explain to me why the first approach doesn't work and if
>>> there's another approach that doesn't involve a -tempname-?
>>>
>>> Thanks,
>>>
>>> Steve
>>>
>>> ******************************
>>> clear
>>> scalar drop _all
>>> scalar a = 10
>>> scalar b = 20
>>> scalar c = b + a
>>> scalar dir
>>>
>>> sysuse auto, clear
>>> reg mpg foreign
>>> scalar d = _b[foreign]
>>> scalar e = d + a
>>> scalar dir a d e // "e" is wrong
>>>
>>> tempname dd
>>> scalar `dd' = _b[foreign]
>>> scalar e = `dd' +a
>>> scalar dir a `dd' e // "e" is /okay
>>> ****************************
>>>
>>> --
>>> Steven Samuels
>>> sjsamuels@gmail.com
>>> 18 Cantine's Island
>>> Saugerties NY 12477
>>> USA
>>> Voice: 845-246-0774
>>> Fax:    206-202-4783
>>>
>>> *

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