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st: Question about scalars

From   Steve Samuels <>
Subject   st: Question about scalars
Date   Mon, 9 Aug 2010 13:57:56 -0400

In the code below, I generate a scalar "d" from a regression result;
it looks okay, but trying to add it to another scalar doesn't work.
If, however I use a -tempname- , I get the right answer.  Could
someone explain to me why the first approach doesn't work and if
there's another approach that doesn't involve a -tempname-?



scalar drop _all
scalar a = 10
scalar b = 20
scalar c = b + a
scalar dir

sysuse auto, clear
reg mpg foreign
scalar d = _b[foreign]
scalar e = d + a
scalar dir a d e // "e" is wrong

tempname dd
scalar `dd' = _b[foreign]
scalar e = `dd' +a
scalar dir a `dd' e // "e" is /okay

Steven Samuels
18 Cantine's Island
Saugerties NY 12477
Voice: 845-246-0774
Fax:    206-202-4783

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