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st: RE: statalist-digest V4 #3797


From   "Pei Gao" <pg349@medschl.cam.ac.uk>
To   <statalist@hsphsun2.harvard.edu>, <statalist-digest@hsphsun2.harvard.edu>
Subject   st: RE: statalist-digest V4 #3797
Date   Sat, 29 May 2010 14:50:29 +0100

Sent from my HTC

-----Original Message-----
From: statalist-digest <owner-statalist@hsphsun2.harvard.edu>
Sent: 23 May 2010 08:33
To: statalist-digest@hsphsun2.harvard.edu <statalist-digest@hsphsun2.harvard.edu>
Subject: statalist-digest V4 #3797

statalist-digest         Sunday, May 23 2010         Volume 04 : Number 3797



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The digest contains:

 RE: st: Assigning values from a list
 Re: st: Assigning values from a list
 Re: st: How do I graph prediction of mean growth trajectory?
 [none]
 Re: st: How do I graph prediction of mean growth trajectory?
 RE: st: RE: R for Stata Users
 re: st: assigning values from a list
 Re: st: How do I graph prediction of mean growth trajectory?
 Re: st: How do I graph prediction of mean growth trajectory?
 Re: st: How do I graph prediction of mean growth trajectory?

----------------------------------------------------------------------

Date: Sat, 22 May 2010 20:58:23 +0930
From: marietherese.kelly@flinders.edu.au
Subject: RE: st: Assigning values from a list

Thank you all, it seems the inlist command will do what I want, I will also
check out egen, anymatch.

I'll also multiply the DSM codes (disease codes) by 100 like you suggested. 

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------------------------------

Date: Sat, 22 May 2010 21:21:17 +0930
From: marietherese.kelly@flinders.edu.au
Subject: Re: st: Assigning values from a list

Sorry I should clarify what var1 and var4 are:

When a patient presents to the clinic, they can be diagnosed with at least one
but up to 4 diseases, entered into var1-4 as codes from the Diagnostic and
Statistical Manual version 9.0. Var1 will always have a value but the remaining
var2-4 may or may not be missing, depending on the diagnosis. So if I want to
find patients suffering from a group of viral illnesses, I would have to search
all 4 variables for the codes 53.20, 54.43 etc up to 76.90

I need to search all var1-4 for every one those codes to make sure I don't miss
any cases. But there are many cases where at least one of var2-4 are missing. 
In that case it might be better to step through through the variables one by
one

I also tried doing this using a
 
local varlist var1 var2 var3 var4
gen virus=.
foreach var in varlist {
 if virus !=. {
   replace virus=1 if ((`var'==53.20) |(`var'==54.42) |(`var'==54.43) | ///
   (`var'==76.00) |(`var'==76.90))
 }
} 

command, but I wasn't aware of the command inlist when I wrote that. 


Similarly if I want to find other groups of diseases (eg fungal infections) I
need to search var1-4 for a different list of DSM codes.

There are about 20 groups of diseases that I need to identify. To complicate
things patients can have multiple diagnoses so I need to make a judgement call
about which one is more serious - var1 takes precedence.



On Thu, May 20, 2010 at 8:49 PM,  <marietherese.kelly@flinders.edu.au> wrote:
> Hi All,
> I was wondering if someone would help me with a basic programming questions.
>
> I have 4 variables that are basically DSM codes and I would like to search
> through those codes.
>
> I would like to define lists of diseases and then pick which cases have those
> diseases
>
> So instead of writing
>
> gen virus=(var1==53.20) |(var1==54.42) |(var1==54.43) | /*
> */ (var1==76.00) |(var1==76.90)
>
> replace virus=((var2==53.20) |(var2==54.42) |(var2==54.43) | /*
> */ (var2==76.00) |(var2==76.90)) if virus==.
>
> replace virus=((var3==53.20) |(var3==54.42) |(var3==54.43) | /*
> */ (var3==76.00) |(var3==76.90)) if virus==.
>
> replace virus=((var4==53.20) |(var4==54.42) |(var4==54.43) | /*
> */ (var4==76.00) |(var4==76.90)) if virus==.
>
>
> Repeat for several other categories of diseases - ends up with very long and
> confusing code.
>
>
> Is there a way of defining a list eg virus={53.20, 54.42, 54.43, 76.00,
76.90}
>
> and checking to see whether var1-4 have values in the list?
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------------------------------

Date: Sat, 22 May 2010 11:59:12 -0400
From: David Torres <torresd@umich.edu>
Subject: Re: st: How do I graph prediction of mean growth trajectory?

Thanks, Michael, for the help.  I think your suggestion may get my  
closer to where I need to be.  Now I just need to find a quick and  
easy way to graph it so I can sit back and enjoy some old James Bond  
movies today.

Ciao,

Diego
- --------------------------------------------

David Diego Torres, MA(Sociology)
PhD Candidate in Sociology


Quoting Michael Norman Mitchell <Michael.Norman.Mitchell@gmail.com>:

> Dear David
>
>   I think that this is a case where the -margins- command could be  
> your friend. It won't directly draw the graph that you seek, but I  
> think it will be useful for obtaining the adjusted means that you  
> could then use for drawing a graph. I have created an example  
> modeled after your description using the Stata example dataset  
> -nlswork-. I renamed the v
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