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RE: st: Assigning values from a list

From   Nick Cox <>
To   <>
Subject   RE: st: Assigning values from a list
Date   Fri, 21 May 2010 11:56:21 +0100

Austin doesn't have your data, and in broad terms nobody else has
either. So he used a random number generator with a specified seed to
create a fake dataset to show principles. 

Your explanation does not remove the warning about not testing for
decimals. -search precision- for FAQs and articles and manual entries
that say more/ 


Thanks for your reply. You are right, I paraphrased the code and should
have put

if virus==0
instead of
if virus==.

I should have been clearer about what var1-4 are: they contain DSM9.0
codes, so
can contain numbers 00.1 up to 999.99. I am trying to find diseases with
codes 53.20, 54.42, 54.43, 76.00, 76.90 so I want to find which cases of
contain these codes and assign that to a new variable virus.

So I'm not sure what the random number generator is for?


I doubt that code does what you want; in particular, the second
through fourth commands do nothing at all (the first command never
produces a missing value so the if condition is never satisfied).  You
also may run into precision problems; I recommend multiplying your
codes by 100 so they are all integers. Try these two methods to see
which you like better:

clear all
set seed 123
set obs 10000
forv i=1/4 {
 g int var`i'=round(uniform()*3000+5000)
g byte  a=var1==5320|var1==5442|var1==5443|var1==7600|var1==7690
replace a=var2==5320|var2==5442|var2==5443|var2==7600|var2==7690 if a==0
replace a=var3==5320|var3==5442|var3==5443|var3==7600|var3==7690 if a==0
replace a=var4==5320|var4==5442|var4==5443|var4==7600|var4==7690 if a==0
g byte b=0
foreach c in 5320 5442 5443 7600 7690 {
 replace b=1 if inlist(`c',var1,var2,var3,var4)
ta a b

On Thu, May 20, 2010 at 8:49 PM,  <>
> Hi All,
> I was wondering if someone would help me with a basic programming
> I have 4 variables that are basically DSM codes and I would like to
> through those codes.
> I would like to define lists of diseases and then pick which cases
have those
> diseases
> So instead of writing
> gen virus=(var1==53.20) |(var1==54.42) |(var1==54.43) | /*
> */ (var1==76.00) |(var1==76.90)
> replace virus=((var2==53.20) |(var2==54.42) |(var2==54.43) | /*
> */ (var2==76.00) |(var2==76.90)) if virus==.
> replace virus=((var3==53.20) |(var3==54.42) |(var3==54.43) | /*
> */ (var3==76.00) |(var3==76.90)) if virus==.
> replace virus=((var4==53.20) |(var4==54.42) |(var4==54.43) | /*
> */ (var4==76.00) |(var4==76.90)) if virus==.
> Repeat for several other categories of diseases - ends up with very
long and
> confusing code.
> Is there a way of defining a list eg virus={53.20, 54.42, 54.43,
> and checking to see whether var1-4 have values in the list?

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