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Re: st: chi2 on aggregate results


From   mai7777 <mai7777@gmail.com>
To   statalist@hsphsun2.harvard.edu
Subject   Re: st: chi2 on aggregate results
Date   Mon, 10 May 2010 13:24:56 -0400

Thanks for the quick response. I guess it was the "col" option that I
was looking for, but just to confirm: Below, is the Pearson chi2(1) =
 5.9421   Pr =  testing the hypothesis that the proportion of 76.67 in
a sample size of 30 equal to the proportion of 47.22 in a sample size
of 36?


. tabi 23 17 \ 7 19, chi col
           |          col
      row |         1          2 |     Total
-----------+----------------------+----------
        1 |        23         17 |        40
           |     76.67      47.22 |     60.61
-----------+----------------------+----------
        2 |         7         19 |        26
           |     23.33      52.78 |     39.39
-----------+----------------------+----------
   Total |        30         36 |        66
           |    100.00     100.00 |    100.00

          Pearson chi2(1) =   5.9421   Pr = 0.015


On Mon, May 10, 2010 at 1:15 PM, Alan Neustadtl
<alan.neustadtl@gmail.com> wrote:
> Are you looking for something like this?
>
> - tabi 23 17  \ 7 19, chi col -
>
>
>
> On Mon, May 10, 2010 at 1:08 PM, mai7777 <mai7777@gmail.com> wrote:
>> hi,
>> I'm trying to conduct a chi2 on aggregate results to test that the
>> proportions of incidence across two treatments are the same:
>>
>> Treatment 1 has a total of 30 subjects, 23 of which had incidence
>> Treatment 2 has a total of 36 subjects, 17 of which had incidence.
>>
>> How do I do that?
>> Thanks!
>> *
>> *   For searches and help try:
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>> *   http://www.ats.ucla.edu/stat/stata/
>>
>
> *
> *   For searches and help try:
> *   http://www.stata.com/help.cgi?search
> *   http://www.stata.com/support/statalist/faq
> *   http://www.ats.ucla.edu/stat/stata/
>

*
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