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From |
"Buzz Burhans" <buzzb3@earthlink.net> |

To |
<statalist@hsphsun2.harvard.edu> |

Subject |
RE: st: how to find the integral for a portion of a normal distribution. |

Date |
Mon, 3 May 2010 22:42:39 -0600 |

Thanks David. I am with you on this part - I can generate the proportion of responses <1 or >1 easily enough creating Z scores. What I want is the sum of the responses in these two proportions - not the count, but the sum of the response volume produced / accumulated by observations in these two proportions. I can do it in several steps - sorting the obs, and summing over each proportions, i.e. the lowest 27.3% and the remaining 72.7%; but it seems that there must be an easier way to get these two cumulative amounts in a single step. . Buzz Buzz Burhans, Ph.D. Dairy-Tech Group So. Albany, VT / Twin Falls ID Phone: 802-755-6842 Cell: 208-320-0829 Fax VT: 802-755-6842 Fax ID: 208-735-1289 Email: buzzb3@earthlink.net -----Original Message----- From: owner-statalist@hsphsun2.harvard.edu [mailto:owner-statalist@hsphsun2.harvard.edu] On Behalf Of David Muller Sent: Monday, May 03, 2010 10:26 PM To: statalist@hsphsun2.harvard.edu Subject: Re: st: how to find the integral for a portion of a normal distribution. To expand upon Michael's suggestion, -display normal((1 - 2.05)/1.74)- will give you the proportion of responses <=1, and -display 1 - normal((1 - 2.05)/1.74)- will give you the proportion of responses >=1. Note that assuming this normal model for your response you would expect a little over 10% of your responses to be less than 0, which indicates a problem with your assumption if your response is strictly positive. David * * For searches and help try: * http://www.stata.com/help.cgi?search * http://www.stata.com/support/statalist/faq * http://www.ats.ucla.edu/stat/stata/

**References**:**Re: st: how to find the integral for a portion of a normal distribution.***From:*David Muller <davidmull@gmail.com>

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