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Re: st: how to find the integral for a portion of a normal distribution.


From   "Hollis,Michael E" <mhollis@mwdh2o.com>
To   <statalist@hsphsun2.harvard.edu>
Subject   Re: st: how to find the integral for a portion of a normal distribution.
Date   Mon, 3 May 2010 21:01:18 -0700

...you'll then be able to use the standard normal distribution with mean zero and unit variance.

Sent from my iPhone

On May 3, 2010, at 8:49 PM, "Buzz Burhans" <buzzb3@earthlink.net> wrote:

Doesn't your suggestion fit only if the curve is standard normal?, i.e. mean
0, SD 1?

Perhaps my use of integral is incorrect; what I want is the area under the
curve of a normal distribution, mean 2.05, sd 1.75 for the portion >=
threshold =1, and then the portion < 1

Buzz


statalist@hsphsun2.harvard.edu] On Behalf Of Hollis,Michael E
Sent: Monday, May 03, 2010 9:36 PM
To: statalist@hsphsun2.harvard.edu
Subject: Re: st: how to find the integral for a portion of a normal
distribution.

I may be missing something here, but can't you simply use the normal
distribution with mean=proportion z >= some threshold, q=1-p and
variance p(1-p)/n?  No integration involved.

As I said, I might be missing something!

Sent from my iPhone

.ucla.edu/stat/stata/

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