Hello,
I am have a dataset structured in the following manner,
. input unique_id newgp str2 given_ahaid pat_zip trmtgp dis
unique_id newgp given_a~d pat_zip trmtgp dis
1. 1 18001 "A" 1800 1
10
2. 2 18001 "B" 1800 1 15
3. 3 18001 "C" 1800 1 18
4. 4 18002 "A" 1800 1 5
5. 5 18002 "B" 1800 1 3
6. 6 18011 "A" 1801 1 0
7. 7 18011 "C" 1801 1 8
8. 8 18011 "D" 1801 1 9
9. 9 18011 "E" 1801 1 5
10. 10 18012 "B" 1801 1 7
11. 11 18012 "C" 1801 1 10
12. 12 18012 "D" 1801 1 4
13. 13 18012 "E" 1801 1 6
14. 14 18013 "D" 1801 1 9
15. 15 18013 "E" 1801 1 5
16. 16 17001 "A" 1700 0 8
17. 17 17001 "B" 1700 0 9
18. 18 17001 "C" 1700 0 7
19. 19 17002 "A" 1700 0 12
20. 20 17002 "B" 1700 0 8
21. 21 17011 "A" 1701 0 2
22. 22 17011 "C" 1701 0 1
23. 23 17011 "D" 1701 0 6
24. 24 17011 "E" 1701 0 4
25. 25 17012 "B" 1701 0 0
26. 26 17012 "C" 1701 0 17
27. 27 17012 "D" 1701 0 5
28. 28 17012 "E" 1701 0 4
29. 29 17013 "D" 1701 0 6
30. 30 17013 "E" 1701 0 7
31. end
I would like to draw a 50% random sample for this dataset stratified
by trtmtgp (treatment group) and clustered on patient zip code
(pat_zip). I have a simple code to do and have pasted the code below.
However when the code is run I get the error below.
. forvalue i=1/5{
2. clear
3. use bsampletest, clear
4. qui tab trmtgp
5. scalar prnt=0.5 // to set 50 percent
sampling, can change
> the number here
6. qui count if trmtgp==0 // comparision market in beginning year
7. scalar tabgp1=int(r(N)*prnt)
8. qui count if trmtgp==1 // treatment market in beginning year
9. scalar tabgp3=int(r(N)*prnt)
10. *display "tabgp1="tabgp1, "tabgp3=" tabgp3
. gen nsamp=cond(trmtgp==0 , tabgp1, 0) + cond(trmtgp==1, tabgp3, 0)
11.
.
. bsample nsamp, strata (trmtgp) cluster(pat_zip)
12. egen mean_dist=mean(dis)
13. display "_N=" _N, "mean_dis=" mean_dis
14. }
unrecognized command: "resample size must not be great invalid command name
r(199);
Is there anyway to get bsample to draw a 50% random sample with
replacement where it is stratified by treatment group and clustered on
patient zip code?
Thank you for your help,
Wool
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