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From |
"Kieran McCaul" <Kieran.McCaul@uwa.edu.au> |

To |
<statalist@hsphsun2.harvard.edu> |

Subject |
RE: st: easiest way to get chi-square test |

Date |
Wed, 23 Dec 2009 07:15:07 +0800 |

... It's not that clear to me what data you have, but if you have counts for each ethnic group, then you can use these as frequency weights. Something like this: clear* input id tot_asian tot_white group 1 100 200 1 2 50 250 1 3 100 150 2 4 50 250 2 end rename tot_asian count1 rename tot_white count2 list reshape long count, i(id) j(ethnicity) label define ethnicfmt 1 "Asian" 2 "White" label values ethnicity ethnicfmt tab ethnicity group [fw=count], chi2 -----Original Message----- From: owner-statalist@hsphsun2.harvard.edu [mailto:owner-statalist@hsphsun2.harvard.edu] On Behalf Of B Web Sent: Wednesday, 23 December 2009 6:41 AM To: statalist@hsphsun2.harvard.edu Subject: Re: st: easiest way to get chi-square test Sorry - the private reply was unintended. Make believe data: Group 1: Asians: 78% Pacific Islander: 65% White: 54% African American: 53% Group 2: Asians: 77% Pacific Islander: 64% White: 53% African American: 52% Do the groups differ with respect to ethnicity percentages? My data are continuous counts or percents right now: tab group, sum( tot_asian) -- mean # of asians in each group tab group, sum( tot_white) -- mean # of whites in each group tab group, sum( tot_pacisland) tab group, sum( tot_afam) what I want is to create counts variable so I can do a chi-square on ethnicity (2x2 table) So ethnicity (white,pac.island...) Group1: Group2: data table - columns( Id, tot_asian, tot_white ..., group) 1 100, 200, 1 2 50, 250, 1 3, 100, 150, 2 4, 50, 250, 2 this needs to be transformed so I have a leveled variable with counts for each group. http://www.ats.ucla.edu/stat/stata/whatstat/whatstat.htm see the section here: tabulate female ses, chi2 I guess I need to generate the ses variable for races, but they are now all different variables. Sorry for the intrusion. On Tue, Dec 22, 2009 at 2:14 PM, Maarten buis <maartenbuis@yahoo.co.uk> wrote: > --- On Tue, 22/12/09, B Web wrote me privately: >> Null hypothesis is that the group percentages across groups >> are equal (i think) > > The policy on the statalist is not to respond privately for reasons discussed in the Statalist FAQ (see the bottom of every post on > Statalist). > > I am still not clear what it is that you are trying to do. Can you > tell a bit more about your variables and the aim of your analysis? > > -- Maarten > > -------------------------- > Maarten L. Buis > Institut fuer Soziologie > Universitaet Tuebingen > Wilhelmstrasse 36 > 72074 Tuebingen > Germany > > http://www.maartenbuis.nl > -------------------------- > > > > > * > * For searches and help try: > * http://www.stata.com/help.cgi?search > * http://www.stata.com/support/statalist/faq > * http://www.ats.ucla.edu/stat/stata/ > * * For searches and help try: * http://www.stata.com/help.cgi?search * http://www.stata.com/support/statalist/faq * http://www.ats.ucla.edu/stat/stata/ * * For searches and help try: * http://www.stata.com/help.cgi?search * http://www.stata.com/support/statalist/faq * http://www.ats.ucla.edu/stat/stata/

**References**:**Re: st: easiest way to get chi-square test***From:*Maarten buis <maartenbuis@yahoo.co.uk>

**Re: st: easiest way to get chi-square test***From:*B Web <webicky@gmail.com>

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