[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index]

From |
carol white <wht_crl@yahoo.com> |

To |
statalist@hsphsun2.harvard.edu |

Subject |
st: mean of a distribution |

Date |
Sun, 18 Oct 2009 11:05:05 -0700 (PDT) |

Hi, How to calculate the mean of the distribution of a random variable? Take the exponential distribution with the probability density function f(x)=lambda.exp(-lambda.x) where lambda is a constant and x is a random variable. The mean of this distribution is the reciprocal of lambda. If the mean is the expected value of x, which for a continuous random variable E(x) = Integral (x.f(x))dx, how could E(x) be the reciprocal of lambda? Regards, Carol * * For searches and help try: * http://www.stata.com/help.cgi?search * http://www.stata.com/support/statalist/faq * http://www.ats.ucla.edu/stat/stata/

**Follow-Ups**:**Re: st: mean of a distribution***From:*Jeph Herrin <junk@spandrel.net>

**st: RE: mean of a distribution***From:*"Nick Cox" <n.j.cox@durham.ac.uk>

**st: AW: mean of a distribution***From:*"Martin Weiss" <martin.weiss1@gmx.de>

- Prev by Date:
**st: AW: R: Simulation using Stata (flag: 9.2/SE version)** - Next by Date:
**st: AW: mean of a distribution** - Previous by thread:
**st: R: Simulation using Stata (flag: 9.2/SE version)** - Next by thread:
**st: AW: mean of a distribution** - Index(es):

© Copyright 1996–2016 StataCorp LP | Terms of use | Privacy | Contact us | What's new | Site index |