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st: RE: extracting month and year from a date variable


From   "Mert Demir" <demirmrt@gmail.com>
To   <statalist@hsphsun2.harvard.edu>
Subject   st: RE: extracting month and year from a date variable
Date   Thu, 27 Aug 2009 00:52:22 -0400

Try this:

g mydate=date(date, "MDY")  /* Second "date" is the 'original date
variable'. 
format mydate %td
g dm=mofd(mydate)
format dm %tm
drop mydate

Hope it works.

Best,



-----Original Message-----
From: owner-statalist@hsphsun2.harvard.edu
[mailto:owner-statalist@hsphsun2.harvard.edu] On Behalf Of Ariel Linden,
DrPH
Sent: Wednesday, August 26, 2009 11:37 PM
To: statalist@hsphsun2.harvard.edu
Subject: st: extracting month and year from a date variable

Hi Fellow Stata Listservers,

I am trying to generate a variable that contains only the month and year,
extracted from another complete date variable. The ultimate intent is to
aggregate a given outcome by the month/year.

So for example, the original date value is 17374, which is displayed as
07/27/2007. I would like to generate a variable that is "Jul 2007" or
"07_2007" (I am not picky on the style, this is just to allow me to
aggregrate by this variable).

I get the feeling that I will have to convert this to a string and then
generate the variable with a substr statement, but I hope there is an easier
way.

Thanks in advance

Ariel 

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