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From |
"Glenn Goldsmith" <glenn.goldsmith@gmail.com> |

To |
<statalist@hsphsun2.harvard.edu> |

Subject |
RE: Re: st: random split |

Date |
Sun, 12 Apr 2009 22:38:17 +0100 |

Hi, If you want exactly 267 in the first group, won't the following achieve this exactly? gen u = runiform() sort u gen split = _n <= 267 More generally (i.e. with _N!=800), you could use -ceil(_N/3)- or -floor(_N/3)- to get 1/3, rounded up or down as desired. HTH, Glenn "Martin Weiss" <martin.weiss1@gmx.de> wrote: <> "exactly a third of observations in the desired group" How do you know that the split will be exact. Even leaving aside the question whether ".33" is close enough to one third to warrant the statement, the uniform number generator will still be noisy, i.e. the true proportion will most likely be different from 1/3... HTH Martin * * For searches and help try: * http://www.stata.com/help.cgi?search * http://www.stata.com/support/statalist/faq * http://www.ats.ucla.edu/stat/stata/

**Follow-Ups**:**Re: Re: st: random split***From:*"Martin Weiss" <martin.weiss1@gmx.de>

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