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Re: st: RE: twoway scatter returns "unmatched quote"


From   Richard Ochmann <rochmann@diw.de>
To   statalist@hsphsun2.harvard.edu
Subject   Re: st: RE: twoway scatter returns "unmatched quote"
Date   Mon, 16 Mar 2009 16:28:41 +0100

does this do what you want?

***
label define status 0 "rural", modify
label values status status
tab status
***

assuming the variable "status" exists.

best, rich




Rike <silvery.enigma@gmail.com> 
Gesendet von: owner-statalist@hsphsun2.harvard.edu
16.03.2009 16:16
Bitte antworten an
statalist@hsphsun2.harvard.edu


An
statalist@hsphsun2.harvard.edu
Kopie

Thema
Re: st: RE: twoway scatter returns "unmatched quote"






I added "modify"

label define status 0 "rural", modify

is what I did (sorry). But

ta status

returns

0

1 urban





On Mon, Mar 16, 2009 at 11:10 AM, Friedrich Huebler <fhuebler@gmail.com> 
wrote:
> Rike,
>
> What do you mean by "it doesn't add a label for 0"? Stata can assign
> labels to zeros. Did you forget the -modify- option?
>
> . sysuse auto
> . d foreign
>              storage  display     value
> variable name   type   format      label      variable label
> ------------------------------------------------------------
> foreign         byte   %8.0g       origin     Car type
>
> . lab list origin
> origin:
>           0 Domestic
>           1 Foreign
>
> . lab def origin 0 "Rural", modify
> . lab list origin
> origin:
>           0 Rural
>           1 Foreign
>
> . tab foreign
>   Car type |      Freq.     Percent        Cum.
> ------------+-----------------------------------
>      Rural |         52       70.27       70.27
>    Foreign |         22       29.73      100.00
> ------------+-----------------------------------
>      Total |         74      100.00
>
> Friedrich
>
> On Mon, Mar 16, 2009 at 10:54 AM, Rike <silvery.enigma@gmail.com> wrote:
>> Hi,
>>
>> I think the problem lies in the label. The variable "status"" takes 0
>> for rural and 1 for urban, but I'm not able to assign a label to 0
>> (and "urban" is already assigned to 1). I ran
>>
>> la def status 0 "rural"
>>
>> it doesn't add a label for 0 which is odd...
>>
>>
>> On Mon, Mar 16, 2009 at 7:21 AM, Nick Cox <n.j.cox@durham.ac.uk> wrote:
>>> No quotes are included in what you report here as typed.
>>>
>>> So, check out in turn
>>>
>>> 1. Any unmatched quotes in the variable label of -status-.
>>>
>>> 2. Any unmatched quotes in the value labels of -status- (if any).
>>>
>>> 3. Any unmatched quotes in the values of -status- (if it is a string
>>> variable).
>>>
>>> 4. Repeat 1 for your other variables.
>>>
>>> My guess is #1.
>>>
>>> Then remove the unmatched quote _or_ insert a matching quote and 
reissue
>>> the -graph- command.
>>>
>>> Nick
>>> n.j.cox@durham.ac.uk
>>>
>>> Rike
>>>
>>> I tried it without the space (I mistakenly put it back there when I
>>> copied the code for the list) but I get the same error. Any other
>>> ideas?
>>>
>>> Kieran McCaul
>>>
>>>> You have a space in the -by- option.
>>>> -by (status)- should be -by(status)-
>>>
>>> Rike
>>>
>>>> I'm running the following code:
>>>>
>>>> twoway scatter ratio month, by(status) c(l) xlabel(1(1)12)
>>>>
>>>> twoway scatter ratio1 ratio2 ratio3 ratio4 month, by (status)
>>>> connect(l l l l) xlabel(1(1)12)
>>>>
>>>> where status is a dummy. Stata returns an r(198) error, and it
>>>> happened when I added the by-option. I would also like to use
>>>> by(status, total) later on. Any suggestions? Thanks in advance.
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