Thanks Carlo - that worked!
I don't suppose you (or anyone else) know about adjusting KM?
I am not even sure if it make sense to adjust survival functions?
I can adjust by one factor i.e: age shown below:
sts,by(group) fail adjustfor(age) ylabel(0 0.1 0.25) tmax(2)
but what about for multiple factors - can't get the coding right
Really appreciate this help as I am a newy!
Many thanks
Sarah
On Thu, Feb 5, 2009 at 12:26 PM, Carlo Lazzaro
<[email protected]> wrote:
> Dear Sarah,
> as far as
> <How do I cut off KM at, say, 4 years follow-up ?>
> Try (Stata 9/2 SE)
> - sts graph, tmax(4)-
>
> HTH and Kind Regards,
> Carlo
>
> -----Messaggio originale-----
> Da: [email protected]
> [mailto:[email protected]] Per conto di sarah keys
> Inviato: giovedì 5 febbraio 2009 10.51
> A: [email protected]
> Oggetto: st: Kaplan meier graphs
>
> Kaplan meier graphs
>
> I am using a multiple record data set. and have Stset as below:
>
> stset date_visit if chc!="", enter(all) fail(chcstop) id(client_id)
> origin(startn)scale(365.25)
>
> *** and had the final cox model:
> xi: stcox i.group age bffa i.w50s
>
> I produced KM graph with the following commands:
>
> sts,by(group) fail ylabel(0 0.05 0.1) risktable
> graph export chc.emf, replace
>
>
> My questions are:
> Can I adjust the KM in the same way as the COX model (adjust by age
> bffa i.w50s)to compare group 1 and group 2?
> How do I cut off KM at, say, 4 years follow-up ?
> Thanks for help
> Sarah
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>
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>
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