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st: RE: RE: graphing problem


From   "Mak, Timothy" <timothy.mak07@imperial.ac.uk>
To   <statalist@hsphsun2.harvard.edu>
Subject   st: RE: RE: graphing problem
Date   Fri, 5 Dec 2008 16:18:28 -0000

Hi Martin, 

Thanks for the article. However, as the article says, Stata determines
the minimum range of the graph according to the range of the data. It
remains impossible to set the range of the graph to be smaller than that
of the data. 

Tim

-----Original Message-----
From: owner-statalist@hsphsun2.harvard.edu
[mailto:owner-statalist@hsphsun2.harvard.edu] On Behalf Of Martin Weiss
Sent: 05 December 2008 15:17
To: statalist@hsphsun2.harvard.edu
Subject: st: RE: graphing problem


Line for the server...

Try http://www.stata-journal.com/sjpdf.html?articlenum=gr0019


HTH
Martin

-----Original Message-----
From: owner-statalist@hsphsun2.harvard.edu
[mailto:owner-statalist@hsphsun2.harvard.edu] On Behalf Of Mak, Timothy
Sent: Friday, December 05, 2008 4:15 PM
To: statalist@hsphsun2.harvard.edu
Subject: st: graphing problem

Hi Statalist, 

I'm joining the list again after a period of absence. For some reason, I
don't seem to be able to send directly to
statalist@hsphsun2.harvard.edu, but if I reply to a post, then it seems
to get there. My original message was as follows: 

Hi Statalist, 

 

Is there any reason why Stata won't let you draw a graph whose y-axis'
range is less than the actual range of the data? Is there a way to get
round this? 

 

The motivation comes from doing a graph where there is one group which
has a articularly large y value. If I graph it with the other groups,
then all the other groups will be very small, and their relative heights
not very distinguishable. If I can focus on the other groups and let the
outlying group 'goes off the scale', that's clearly quite a good device
to have. In fact, the problem can't be overcome even if I artificially
set the outlying y value to the maximum of the y range, because the top
will look different, particularly when I want to graph error intervals. 

 

Thanks for your help. 

 

Tim

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