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Re: st: Loop over variables with svyset


From   "Daniel Schultz" <schultzd@tcd.ie>
To   statalist@hsphsun2.harvard.edu
Subject   Re: st: Loop over variables with svyset
Date   Fri, 21 Nov 2008 11:35:34 +0000

Sorry for not mention the error.
I thought that the error message is clear, due to my description.
The error message is, that a variable is not found. This is due to the
fact, that I don't have every variable for every year. Which is the
reason why I need a loop like the one Steven posted. But which shows
respect to the fact, that some variables are missing. (concerning the
year).

Hope this was explanation enough.

2008/11/19 Friedrich Huebler <fhuebler@gmail.com>:
> Daniel,
>
> First, you don't say which error you encounter. Please elaborate.
> Second, you can include a -di- command  in your loop to check if the
> values of k are the values you need.
>
> capture {
>  forvalues k=1/3 {
>    if `k' < 100 local k 0`k'
>    if `k' < 10 local k 0`k'
>    di "k = `k'"
> etc.
>
> Friedrich
>
> On Wed, Nov 19, 2008 at 12:57 PM, Daniel Schultz <schultzd@tcd.ie> wrote:
>> Ok thanks for all the comments...
>> with the -capture block the do-file is running,
>> BUT
>> is actually producing no output after the first error.
>> This is the part of my do-file (to make it more quick only until Number 3)
>>
>> capture {
>> forvalues k=1/3{
>> if `k' < 100 local k 0`k'
>> if `k' < 10 local k 0`k'
>>  forvalues year=2/7 {
>>  svyset [pw=Q1170_0`year']
>>  svy: tab Q0`k'_0`year'
>> mat Q0`k'_0`year' = (e(Prop)\e(total))
>> }
>> }
>> }
>>
>> The first error occurs after the first run of the second forvalues
>> (forvalues year=2/7 {) loop (number 3).
>> With the capture block, the do-file is working, but the mat command
>> only produces a matrix until the first error (a matrix only for year
>> =2). Thus, I assume, that it is not working totally.
>>
>> With adding -noisily the do file stops when the first error occurs.
>> Best
>> Daniel
>>
>>
>> 2008/11/19 Buzz Burhans <buzzb3@verizon.net>:
>>> server
>>>
>>> Steve wrote
>>> "Just be aware that  captured statements, whether they produce errors
>>> or not,  show no output."
>>>
>>>
>>> -capture noisily {
>>> ...
>>> }-
>>>
>>> will produce output if the command does not fail and would otherwise produce
>>> output.
>>>
>>> So capture, with noisily added, should give you output, unless the command
>>> fails
>>>
>>> Buzz Burhans
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