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From |
"Nick Cox" <n.j.cox@durham.ac.uk> |

To |
<statalist@hsphsun2.harvard.edu> |

Subject |
RE: st: using _all |

Date |
Thu, 28 Aug 2008 13:06:32 +0100 |

Eva is correct, as usual. Some further notes for Ashim and anyone interested: The syntaxes -foreach ... in ...- and -foreach ... of ...- are very different. With the first -foreach- takes what you typed and treats it very literally. There is no translation, expansion, or substitution. With the second -foreach- is inclined to expand whatever is specified afterwards, e.g. a varlist specified as such will be expanded to the constituent variable names. With this code . foreach x in _all { replace `x'=`x'[_n-1] if _n==_N } You have specified a list with a single item, namely _all, and -foreach- pays no attention to what the item means. It is entirely as if you have specified replace _all = _all[_n-1] if _n == _N which happens to be illegal. So, the -foreach- specification is legal, but what it implies within the loop is not. To drive that home, consider this foreach x in _all { d `x' } The example is dopey, but it illustrates that you could have a perfectly legal example. (Why is it dopey? Because there is little point in setting up a loop with a single item. Because -d _all- is just more easily written -d-.) Nick n.j.cox@durham.ac.uk P.S. On a different note, what you are doing seems a bit odd, but there is another way to do it: drop in L expand 2 in L Eva Poen you want to change the first line: foreach x of varlist _all { Ashim Kapoor > I wish to replace the last obs of EACH variable by the previous value. > But when I do this : - > . foreach x in _all { > replace `x'=`x'[_n-1] if _n==_N > } > > it does'nt work.! * * For searches and help try: * http://www.stata.com/help.cgi?search * http://www.stata.com/support/statalist/faq * http://www.ats.ucla.edu/stat/stata/

**References**:**st: using _all***From:*"Ashim Kapoor" <ashimkapoor@gmail.com>

**Re: st: using _all***From:*"Eva Poen" <eva.poen@gmail.com>

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