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st: =?utf-8?B?UmU6IEhvdyB0byBydW4gbG9vcHMgd2l0aCBvdXRyZWcgKHdhcyBzdDogSG93IHRvIHJlZ3Jlc3MgYW5kIG91dHJlZyBieXllYXI/KQ==?=


From   "=?utf-8?B?Wml5YW5nIFdhbmc=?=" <wzmartin@ust.hk>
To   "=?utf-8?B?c3RhdGFsaXN0QGhzcGhzdW4yLmhhcnZhcmQuZWR1?=" <statalist@hsphsun2.harvard.edu>
Subject   st: =?utf-8?B?UmU6IEhvdyB0byBydW4gbG9vcHMgd2l0aCBvdXRyZWcgKHdhcyBzdDogSG93IHRvIHJlZ3Jlc3MgYW5kIG91dHJlZyBieXllYXI/KQ==?=
Date   Thu, 15 May 2008 13:58:54 +0800

Hi Roy Wada,

I see this solution, but not so sure how does the following two lines work:
  outreg using myfiles, `append'
     local append "append" 

Can anyone please explain a little? In the first line, without previous definition of append, what's their initial value? what if in the first loop I want to use "replace" option, and in the following I want to use "Append"?

Thanks,

Martin

======= 2008-05-15 02:04:39 Original Message:=======

>
>Here's a template on running loops with outreg:
>
>* data setup
>cd d:\
>sysuse auto, clear
>gen id=0
>replace id=1 in 16/45
>ren foreign year
>levelsof year
>
>* the relevant part
>foreach var in `r(levels)' {
>     xi: areg price mpg turn i.rep if year==`var', absorb(id)
>     outreg using myfiles, `append'
>     local append "append" 
>}
>
>
>Here's the original solution:
>
>http://www.stata.com/statalist/archive/2004-06/msg00231.html
>
>
>
>>Dear all,
>>
>>May I ask a novice question? I'm really new to Stata. I want to run regression 
>>by year and the outreg the coefficients for each year. I want to use like :
>>by year: xi: areg score age education , absorb(nation), but stata tells me "by" 
>>can not be combined with xi. Anyone has good solutions? Also I don't think 
>>using by can outreg coefficients for each year.
>>
>>Many thanks in advance!
>>
>>Best,
>>
>>Martin
>
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