[Date Prev][Date Next][Thread Prev][Thread Next][Date index][Thread index]

From |
Kit Baum <baum@bc.edu> |

To |
statalist@hsphsun2.harvard.edu |

Subject |
st: re: z-score as a dependent variable |

Date |
Fri, 16 Nov 2007 13:25:14 -0500 |

Ana said

Sorry to jump into this but I dont see whay Dan cannot

use z-scores as a dependent variable, even if z-scores

are standarized. Wouldnt it depend on which are the

independent variables used?

No, no reason why not, and it actually doesn't depend on the regressors. If you run

z(y) = a + b X + u

b is the number of standard deviations of y in response to a one unit change in X. If that makes sense as a way to express dY/dX, fine. If you run

z(y) = b z(X) + u

you are calculating the 'beta coefficient', i.e. regress y X, beta.

Kit Baum, Boston College Economics and DIW Berlin

http://ideas.repec.org/e/pba1.html

An Introduction to Modern Econometrics Using Stata:

http://www.stata-press.com/books/imeus.html

*

* For searches and help try:

* http://www.stata.com/support/faqs/res/findit.html

* http://www.stata.com/support/statalist/faq

* http://www.ats.ucla.edu/stat/stata/

- Prev by Date:
**Re: st: z-score as a dependent variable in a linear regression** - Next by Date:
**st: Testing non-proportionality in a discrete-time survival model in which the main effect of time is treated as continuous.** - Previous by thread:
**st: re: a stata question** - Next by thread:
**st: Testing non-proportionality in a discrete-time survival model in which the main effect of time is treated as continuous.** - Index(es):

© Copyright 1996–2014 StataCorp LP | Terms of use | Privacy | Contact us | What's new | Site index |