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From |
"Nick Cox" <n.j.cox@durham.ac.uk> |

To |
<statalist@hsphsun2.harvard.edu> |

Subject |
st: RE: Loop question |

Date |
Fri, 28 Sep 2007 15:42:09 +0100 |

I take it the typical observation (case, record) is for a patient's visit and includes -arrdt- and -dcdt-. I think a loop may be needed _with this data structure_. gen already = . qui forval i = 1/`= _N' { count if arrdt < arrdt[`i'] & dcdt > dcdt[`i'] replace already = r(N) in `i' } It is easier in a different data structure which has two observations for every patient visit. Then you create a score +1 for an arrival and -1 for a departure and use -sum()- to get the number in the queue. Subtract 1 to get -already-. This different data structure could be got via -reshape long-. Other questions about timing would I think always be easier in that data structure. -search count- to find a reference to Stata Journal tutorials on how useful -count- can be. Nick n.j.cox@durham.ac.uk Steve Pitts > I'm trying to work out how many patients are already present > in an emergency > department (a variable called "how_busy") for each member in > a list of > patients that includes the variables "arrival datetime" and > "discharge > datetime", i.e. I'd like to know how many patients preceding > the index > patient have dcdt > current arrdt in a list of visits sorted > by arrdt. I'm > no programmer and fairly new to Stata, and haven't been able > to make it work > using -forval- and -while- loops with explicit subscripting. > Maybe there's a > clever way to do this using -egen-? > > An alternative "how_busy" measure might be a count of all > patients who were > in the ED during any part of the index patient's visit (maybe > it got busy > later). I think this would need to be divided by length of > stay. In any case > for me: equally impossible, but maybe this is easy for someone else. * * For searches and help try: * http://www.stata.com/support/faqs/res/findit.html * http://www.stata.com/support/statalist/faq * http://www.ats.ucla.edu/stat/stata/

**References**:**st: Loop question***From:*"Steve Pitts" <pittssteve@gmail.com>

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