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From |
SamL <saml@demog.berkeley.edu> |

To |
statalist@hsphsun2.harvard.edu |

Subject |
Re: st: Sampling scheme |

Date |
Thu, 12 Jul 2007 16:14:01 -0700 (PDT) |

Yes. I would proceed as follows: gen group=yourvariable recode group (11/13=1) (21/23=2) (31/33=3) sort group <---not sure this is needed set seed ******* <---pick a number, so you can reproduce results by group: sample 25, count makes it give you a sample of 25 units for each group, without count it will sample 25% of each group. I think this'll work to give you the samples you need. Hope this helps. Sam On Thu, 12 Jul 2007 tiago.pereira@incor.usp.br wrote: > Dear statalisters, > > I have a variable in which observations take one out of 9 values: > 11,12,13,21,22,23,24,31,32,33 > > So, observations assume the values 1`i', 1`i', 3`i', for i = 1,2 or 3. > > Assuming that I have 1000 observations , I would like to: > > (1) randomly sample, say, 25 observations satisfying the condition ==1`i' > > (2) randomly sample 50 observations satisfying the condition ==2`i' > > (3) randomly samply another 25 observations satisfying the condition ==3`i' > > Then, I would like to count the frequency of each `i' in the first, second > and last samplings. > > For example, considering yet the example above, assume that among the > first sampling (25 obs), 12 observations were 1`3', 10 were 1`1' and 3 > were 1`2' (12+10+3 = 25 sampled observations). > > I would like to obtain the following result: > > `1' = 10 > `2' = 03 > `3' = 12 > > > Is it possible to perfom such sampling scheme using Stata? > > Thank you very much. > > Tiago > > > * > * For searches and help try: > * http://www.stata.com/support/faqs/res/findit.html > * http://www.stata.com/support/statalist/faq > * http://www.ats.ucla.edu/stat/stata/ > * * For searches and help try: * http://www.stata.com/support/faqs/res/findit.html * http://www.stata.com/support/statalist/faq * http://www.ats.ucla.edu/stat/stata/

**References**:**st: Sampling scheme***From:*tiago.pereira@incor.usp.br

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