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Re: st: Re: programming assist, too many unique values forlevels


From   "Andrew O'Connor DO" <aoconnor@metrohealth.org>
To   <statalist@hsphsun2.harvard.edu>
Subject   Re: st: Re: programming assist, too many unique values forlevels
Date   Tue, 01 May 2007 16:25:36 -0400

thank you
Andrew O'Connor, DO, MPH
Division of Nephrology
Center for Healthcare Research and Policy
MetroHealth Medical Center/Case Western Reserve University
(216)778-8484
>>> michael.blasnik@verizon.net 05/01/07 4:19 PM >>>
You don't need the levels command or the loops at the end, just use
-egen- 
commands:

egen time=sum(obstime), by(pt)
egen time_out=sum(out_range), by(pt)
gen bphigh=bp_systolic >= `threshold' & bp_systolic !=.
egen proportion=mean(bphigh), by(pt)

I think the above code should replace about 25 lines of your code. 
Note, I used 
egen sum(), but egen total() is a newer synonym, as is moving the -by-
to a 
prefix, but it will work fine as shown.

Michael Blasnik


----- Original Message ----- 
From: "Andrew O'Connor DO" <aoconnor@metrohealth.org>
To: <statalist@hsphsun2.harvard.edu>
Sent: Tuesday, May 01, 2007 2:54 PM
Subject: st: programming assist, too many unique values for levels


<snip>
> I've run into a problem due to the size of my data set, specifically
> that I have too many levels.  Here is my code
<snip>
> gen time=.
>
> levels pt, local(levels)
> quietly foreach l of local levels {
> sum obstime if pt==`l'
> local total=r(sum)
> replace time=`total' if pt==`l'
> }
> gen time_out=.
> quietly foreach l of local levels {
> sum out_range if pt==`l'
> local total =r(sum)
> replace time_out=`total' if pt==`l'
> }
> gen time_o_r=(time_out/time)
> local threshold = 140
>  gen proportion=.
> levels pt, local(levels)
> quietly foreach l of local levels {
>   count if pt == `l' & bp_systolic !=.
>    local total =r(N)
>    count if bp_systolic >= `threshold' & bp_systolic !=. & pt == `l'
>    replace proportion = r(N)/`total' if pt == `l'
> }
> Any suggestions for using a different set of programming statements???
> Thanks,
> AO
>

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