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RE: st: monthly means & CI


From   Ana Gabriela Guerrero Serdan <ag_guerreroserdan@yahoo.com>
To   statalist@hsphsun2.harvard.edu
Subject   RE: st: monthly means & CI
Date   Wed, 14 Mar 2007 08:36:41 -0700 (PDT)

Dear Nick, Sven and Nicholas, 

Thank you very much! this is very helpful. 

regards, 
Gaby 


--- Nick Cox <n.j.cox@durham.ac.uk> wrote:

> Svend had some very good advice here. 
> 
> Here's some more. 
> 
> 0. Whatever you do, it seems that you should look at
> 
> 
> females / (males + females) 
> 
> and also 
> 
> females / (males + females + unknown) 
> 
> 1. Plot your means against month. 
> 
> 2. If there's no seasonality there is little point 
> to splitting by month. 
> 
> 3. If there is seasonality, the tacit assumption
> that
> separate months are mutually independent is
> unlikely. One
> way forward is a generalised linear model with
> binomial link and time of year as predictor. 
> A trigonometric approach might help. See
> 
> SJ-6-4  st0116  . . . .  Speaking Stata: In praise
> of trigonometric predictors
>         Q4/06   SJ 6(4):561--579                    
>             (no commands)
>         discusses the use of sine and cosine as
> predictors in
>         modeling periodic time series and other
> kinds of periodic
>         responses
> 
> Nick 
> n.j.cox@durham.ac.uk 
> 
> Svend Juul
>  
> > Gaby Serdan wrote:
> > 
> > I have data on deaths. I need to calculate the
> mean &
> > CI of females in proportion to all population. Im
> > trying first to create a variable for each month
> then
> > take the total number of female per month and then
> > divide by total number of deaths per month. 
> > 
> > - and Clive Nicholas gave suggestions.
> >
>
---------------------------------------------------------------
> > 
> > I understand that you want to estimate the
> proportion
> > of females among the persons who died each month.
> The
> > data you provided are a bit surprising for the
> purpose,
> > with one female, three males, and 21 with unknown
> sex.
> > To create some more illustrative data, I:
> > 
> 
> 
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