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st: RE: Pearson's chi squared test


From   "Maarten Buis" <M.Buis@fsw.vu.nl>
To   <statalist@hsphsun2.harvard.edu>
Subject   st: RE: Pearson's chi squared test
Date   Wed, 27 Sep 2006 15:59:40 +0200

André:
H0 is independence, i.e. no relation between rows and columns.
In your case you reject the hypothesis that the rows and columns are independent.
HTH,
Maarten

-----------------------------------------
Maarten L. Buis
Department of Social Research Methodology 
Vrije Universiteit Amsterdam 
Boelelaan 1081 
1081 HV Amsterdam 
The Netherlands

visiting adress:
Buitenveldertselaan 3 (Metropolitan), room Z434 

+31 20 5986715

http://home.fsw.vu.nl/m.buis/
-----------------------------------------

-----Original Message-----
From: owner-statalist@hsphsun2.harvard.edu [mailto:owner-statalist@hsphsun2.harvard.edu]On Behalf Of André Paul
 I was wondering what the null hypothesis is for Pearson's test after a two
way tabulation.
Is it that there is no relationship between column and rows or that there is
one?

For example, how is this result to be interpreted?
Pearson chi2(6) =184.1900 Pr = 0.000


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