If your data include only 10 states, then it's
more like
decode id, gen(ID)
forval i = 1/10 {
local label = ID[`i']
xtline ... if id == `i', subtitle("`label'")
}
or
forval i = 1/10 {
xtline ... if id == `i', subtitle("`= ID[`i']'")
}
Nick
n.j.cox@durham.ac.uk
-----Original Message-----
From: owner-statalist@hsphsun2.harvard.edu
[mailto:owner-statalist@hsphsun2.harvard.edu]On Behalf Of Scott
Cunningham
Sent: 06 September 2006 18:23
To: statalist@hsphsun2.harvard.edu
Subject: Re: st: RE: xtline with labels
Thanks Nick. -ecode- and -decode- are new to me. I'm looking it up
now.
10 states - I'm only looking at 10 states right now.
scott
On Sep 6, 2006, at 1:18 PM, Nick Cox wrote:
First off, you need to read up some basics on -encode-
and -decode-.
I know of 50 U.S. states, so I am not clear how you get
10 different graphs with 10 different states on each.
I guess 10 different graphs with 5 states on each.
First, you have to set up your grouping in advance.
Let a variable -group- indicate each subset of states.
Set it up so that the values run from 1 to 10.
A minimal recipe which you will want to complicate is
decode id, generate(ID)
forval i = 1/10 {
levelsof ID, local(IDS) clean
xtline sexratio if group == `i', subtitle("`IDS'")
}
Nick
n.j.cox@durham.ac.uk
Scott Cunningham
I have a small dataset containing the ratios of men to women for
blacks and whites at the United States level that varies by age. I
want to use -xtline- to create 10 different graphs, with
the name of
10 different U.S. states above each graph. The data is tsset as:
. tsset id age
where "id" is a numerical identifier of a United States state
and age
is the sex ratio for that state at different ages. I've
labeled the
values of "id" using "label define idlbl # [name]" so that
each value
has its accompany US State. Is there a way to cause xtline
to report
the names of each state used to create each independent sex ratio?
Because, when I do this:
. xtline sexratio
it reports a number above each graph.
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