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Re: st: RE: regular expressions in Stata


From   scott hankins <scott.hankins@gmail.com>
To   statalist@hsphsun2.harvard.edu
Subject   Re: st: RE: regular expressions in Stata
Date   Tue, 13 Sep 2005 13:54:58 -0400

The "V" is there because I am an idiot :) and tried to do two things
at once. Thanks for taking time to help.

scott

p.s. thanks as well for all of your effort with this list, I have
learned a lot from you in the last couple of years.


On 9/13/05, Nick Cox <n.j.cox@durham.ac.uk> wrote:
> "76(4|5).3"
> 
> and
> 
> "^76(4|5).3"
> 
> both seem to work here. What's that "V" doing?
> 
> Nick
> n.j.cox@durham.ac.uk
> 
> scott hankins
> 
> > I am trying to use the new regex functions and am having some issues.
> >
> > I am familiar (but not an expert) with regular expressions in Perl and
> > I am problems applying that knowledge in Stata. Does anyone know how
> > regular expressions are implemented in Stata? Ideally, I would like
> > more than "Regular expression syntax is based on Henry Spencer's NFA
> > algorithm and as such, is nearly identical to the POSIX.2 standard."
> > as I have not been able to find a clear exposition of the POSIX.2
> > standard online (I am sure there is one, I just can't find it :) ).
> >
> >
> > ***********************************
> > here is my problem
> >
> > pdx
> > 76403
> > 76403
> > 76513
> > 76503
> >
> >
> > I tried the following code but it did not find any matches, this
> > should find all 4 of the above occurrences.
> >
> > replace weight = 3 if regexm(pdx,"V76(4|5).3")
> 
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