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RE: st: RE: how to use lag function to create sequential number


From   "Nick Cox" <n.j.cox@durham.ac.uk>
To   <statalist@hsphsun2.harvard.edu>
Subject   RE: st: RE: how to use lag function to create sequential number
Date   Sun, 11 Sep 2005 19:47:53 +0100

This has the solution I gave previously. Do try it. 

Nick 
n.j.cox@durham.ac.uk 

mzhang@nd.edu
 
> Sorry I did not state my question well. there are different 
> racial groups in my
> sample. What i want to do is to give each racial group a 
> sequential number.
> for example, I have 17 whites, 5 blacks and 7 others. then 
> the value of the
> sequential variable I created would be: 1 2 3....17 for 
> whites; 1 2 ...5 for
> blacks;
> 1 2 ....7 for others. what I was originally thinking is:
> 
> gen sequence=1
> replace sequcence=sequence+1 if l.race==race
> 
> However, this does not work out as I thought.
 
Nick Cox 

> > I am not aware of a lag function, i.e. -lag()-, in Stata. There is
> > a lag operator L. but that is not appropriate for your purpose.
> >
> > You may be in search of
> >
> > bysort race : gen id = _n
> >
> > or
> >
> > bysort race : egen id = seq()
> >
> > although note that the labelling produced is essentially arbitrary
> > in either case.

mzhang@nd.edu

> > > for example, there are 17 people who have the same ethnicity.
> > > If I want to give
> > > them a sequential number 1 2 3..........17, how can I use lag
> > > function to do this?

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