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Re: st: how to use inverse hyperbolic sine function


From   Roger Harbord <roger.harbord@bristol.ac.uk>
To   statalist@hsphsun2.harvard.edu
Subject   Re: st: how to use inverse hyperbolic sine function
Date   Thu, 31 Mar 2005 10:11:58 +0100

There's a typo in Scott's reply below. I'm sure he meant to type

IHS = log(z + sqrt(z^2 + 1))

Roger.

--On 30 March 2005 15:37 -0600 smerryman@kc.rr.com wrote:

An inverse hyperbolic sine transformation is:
 IHS = log(z + sqrt(z^z + 1))

It is an alternative to log transformations when some of
the variables take on zero or negative values and as
an alternative to the Box-Cox when variables are zero or
negative.


See, for example:

Layton, David F, 2001. "Alternative Approaches for Modeling
Concave Willingness to Pay Functions in Conjoint Valuation,"
American Journalof Agricultural Economics, vol. 83(5), 1314-20.

Burbidge, John B., Lonnie Magee and A. Leslie Robb. 1988 "Alternative
Transformations to Handle Extreme Values of the Dependent Variable."
 Journal of the American Statistical Association, vol. 83, 123-127.



Scott


----- Original Message -----
From: wying1@umbc.edu
Date: Wednesday, March 30, 2005 1:40 pm
Subject: st: how to use inverse hyperbolic sine function

Dear users,

I need to use inverse hyperbolic sine function to transform my
dependentvariables in a regression, which, honestly, I don't
understand very much.
I failed to find the relevant commands to perform this technique
in Stata
7.0.  Does anybody have a relevant program which I can use as a
reference,and have suggestions about interpreting the coefficient
for varaibles like
gender?  Thanks a lot.



Ying

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