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From |
Ernest Berkhout <Ernest.Berkhout@seo.nl> |

To |
statalist@hsphsun2.harvard.edu, statalist@hsphsun2.harvard.edu |

Subject |
Re: st: question on bootstrapping of proportions |

Date |
Fri, 18 Mar 2005 11:49:16 +0100 |

At 11:31 18/03/2005, Gijs Dekkers wrote:

Now a classical poverty measure quite popular here in Europe is the headcount ratio. One is poor if one's income is below 60 percent of the median income. In stata-syntaxFor someone using Stata for only 4 days, you're already quite advanced in your code! :-)

by jaar: summarize income [aweight=weight],detail

by jaar: gen byte poor=income < 0.6*r(p50)

by jaar: tabulate poor [aweight=weight]

The only problem is that the above does not do what you want. The 'r(p50)' is a very temporary thing, and it gets overwritten immediately when you do another summarize. So in practice, you are referring to the median of the last year in your dataset.

I think you want something like:

local beginjaar = 1994

local eindjaar = 2002

foreach jaar = `beginjaar' / `eindjaar' {

summarize income [aweight=weight] if jaar==`jaar',detail

gen byte poor=income < 0.6*r(p50) if jaar==`jaar'

tabulate poor [aweight=weight] if jaar==`jaar'

}

Now you use the r(p50) reference to the median DIRECTLY in your calculation.

Ernest Berkhout

SEO Amsterdam Economics

University of Amsterdam

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**References**:**st: question on bootstrapping of proportions***From:*Gijs Dekkers <gd@plan.be>

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