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After this syntax, what is specified 
in -preffect()- will be visible as `preffect'. 
This will be a string (emphatically not 
a string variable). The ` ' are essential. 

di preffect 

by itself will be interpreted as 
a reference to a variable -preffect-, 
in fact to -preffect[1]-, which evidently 
you don't have. 

If you don't have anything compulsory before
the options the syntax should be 

syntax [, PREffect(string)]


> -----Original Message-----
> From: 
> []On Behalf Of 
> Sent: 18 May 2004 19:32
> To: 
> Subject: st: Syntax syntax
> I'm pulling my hair out with this problem - I just can't see what's
> wrong, so any help much appreciated! The problem I'm having contains
> syntax for the "syntax" programming command.
> A program I'm writing includes the line:
> syntax [anything] [, PREffect(string)]
> This is intended to pick-up an optional option called "preffect" (or
> "pre" for short) with the contents of the brackets recorded 
> as a string
> variable.
> The next line of my program is:
> display preffect
> Yet when I run the program specifying the preffect option (including
> something in brackets), the "display" command displays nothing - it
> appears that the contents of the bracket following the preffect
> in the command line have not been picked-up.
> Why not? How can I get my program to pick-up the contents of the
> option?
> (What's the [anything] code about? Without it, I get a "varlist not
> allowed" error. I guess putting [anything] in the program is not
> practice, but I would like to get the options problem sorted out
> first.)
> Thank you very much!
> Dominic Muston.

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