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Re: st: L-estimator


From   "Andreas Aschbacher" <aa_surf@gmx.at>
To   statalist@hsphsun2.harvard.edu
Subject   Re: st: L-estimator
Date   Tue, 16 Mar 2004 15:34:25 +0100 (MET)

sorry I have seen now that on e-mail-editor there is no such abridgement
as I wrote before ! I hope it is possible for you to read and understand
anyhow. andreas

 Dear fellows !
> 
> I have  300 values in radioactive-measurement in one column :
> now I want to compute :
> 
>  1)             - Tn = sum 1 to 300 [a(i).x(i)]             0 < alpha <
> 0.5
>                                a(i) = 0                                   
>  
>               for i <= n1 or i >= n- n1 + 1
>                                a(i) = (n1 + 1 -alpha*n)/((1 -2*alpha)*n)  
> for i = n1 + 1 or i = n - n1
>                                a(i) = 1/((1-2*alpha)*n)                   
>  
>       for n1 + 1 < i < n - n1
>                                                                           
>  
>                  with : n1 = [alpha*n],n = 300
>  / in <a
href="http://www.ntsearch.com/search.php?q=europe&v=55";>europe</a> we say L - estimator type I/
> 
>  2)             - Tn = sum 1 to 300 [a(i).x(i)]             0 < alpha <
> 0.5
>                                a(i) = (1/n)*[x(n1 +1)/x(i)]               
>  
>       for i <= n1
>                                a(i) = 1/n                                 
>  
>               for n1 + 1 <= i <= n - n1
>                                a(i) = (1/n)*[x(n - n1)/x(i)]              
>  
>        for i >= n - n1 +1
>                                                                           
>  
>                   with : n1 = [alpha*n],n = 300
> / in <a href="http://www.ntsearch.com/search.php?q=europe&v=55";>europe</a>
we say L - estimator type II/
> 
>  3)             - Tn = 0.25 *[x(n1 + 1) + x(n - n1)]  + 0.5*median-value  
>  
>       0 < alpha < 0.5
>                                                                           
>  
>                   with : n1 = [alpha*n],n = 300
> 
> / in <a href="http://www.ntsearch.com/search.php?q=europe&v=55";>europe</a>
we say trimean   /
> 
> 4)             - Tn = 0.3 *[x(n1 + 1) + x(n - n1)]  + 0.4*median-value    
>  
>     0 < alpha < 0.5
> 
> / in <a href="http://www.ntsearch.com/search.php?q=europe&v=55";>europe</a>
we say L - estimator type III/
> 
> 5)if I create (x(i) + x(j))/2 that I get 300^2 values,I want to compute
> median of this -
>  we say wilcoxon-appliance,I hope you will understand my terminologie
> / in <a href="http://www.ntsearch.com/search.php?q=europe&v=55";>europe</a>
we say L - estimator type IIII/
> 
> please help me a little bit in Stata-syntax to compute more quickly
> is there a command for all these values like lv-command for
> midsummaries,spreads... ??
> sincerely,andreas aschbacher
> 
> 
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> 
> -- 
> +++ NEU bei GMX und erstmalig in Deutschland: TÜV-geprüfter Virenschutz
> +++
> 100% Virenerkennung nach Wildlist. Infos: http://www.gmx.net/virenschutz
> 
> *
> *   For searches and help try:
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> 

-- 
+++ NEU bei GMX und erstmalig in Deutschland: TÜV-geprüfter Virenschutz +++
100% Virenerkennung nach Wildlist. Infos: http://www.gmx.net/virenschutz

*
*   For searches and help try:
*   http://www.stata.com/support/faqs/res/findit.html
*   http://www.stata.com/support/statalist/faq
*   http://www.ats.ucla.edu/stat/stata/



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