Re: st: SP/RM[1,2] EMS

[David Airey <david.airey@vanderbilt.edu>]

Ken kindly set me right, but left me wondering about Stata's ANOVA 
syntax:


> David has misread the example in the FAQ.  He says that it uses
> MS(E) for the test of P and I (his letters, or period and dial
> the corresponding names for the example in the FAQ).
>
> Look carefully at the -anova- command and at the output shown in
> the FAQ.
>
>     term                 tested using
>     -----------------    --------------------
>     noise                subject|noise
>     period               period*subject|noise
>     noise*period         period*subject|noise
>     dial                 dial*subject|noise
>     noise*dial           dial*subject|noise
>     period*dial          residual
>     noise*period*dial    residual
>
> If I am following the mapping from his names to the FAQ example
> names correctly, it appears that we are in agreement.
>
> By the way, what I present in the FAQ as Stata output of -anova-
> agrees with what Winer, Brown, & Michels show in Table 7.16 where
> they show the ANOVA table for the example dataset.
I guess I would have expected the command syntax to then be:

. anova score noise/subject|noise period/period*subject|noise 
noise*period/perio
> d*subject|noise dial/dial*subject|noise noise*dial/dial*subject|noise 
period*d
> ial noise*period*dial, repeated(period dial)
repeated term
r(141);

which fails,

rather than:

. anova score noise / subject|noise period noise*period / 
period*subject|noise
  dial noise*dial / dial*subject|noise period*dial noise*period*dial ,
  repeated(period dial)

I thought when a term did not specify the denominator, the residual was 
used. In the latter command, the terms period and dial are listed 
without a denominator so I thought they were using the residual. But 
when I look at the output, it's clear they are using a different (and 
correct) denominator. What am I not understanding in telling or not 
telling Stata what I want?

-Dave

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