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st: RE: RE: dates


From   "Vania Gerova" <vania.gerova@employment-studies.co.uk>
To   <statalist@hsphsun2.harvard.edu>
Subject   st: RE: RE: dates
Date   Tue, 1 Apr 2003 17:31:42 +0100

Hi Nick,

thanks for the suggestions!
33824 = 8th August 1992 in Excel.
My variable looks like:

33824
5/25/1995
2/27/1995
33610
5/23/1995
6/22/2000
35550

and so on, 1941 cases in one long column and it's a string.
Vania


-----Original Message-----
From: owner-statalist@hsphsun2.harvard.edu
[mailto:owner-statalist@hsphsun2.harvard.edu]On Behalf Of Nick Cox
Sent: 01 April 2003 16:49
To: statalist@hsphsun2.harvard.edu
Subject: st: RE: dates


Vania Gerova

> I have a string variable containing dates. Unfortunately
> the dates are in
> different formats. One of the formats is a datevalue, like
> 33824, which
> seems to represent  08/08/1992, i.e. dd/mm/yyyy   (European
> format).

. di mdy(8,8,1992) - mdy(1,1,1900)
33822

I have read that there is a bug regarding 29 Feb 1900, which
didn't happen, but did according to some software. I don't know
if that helps or not.

> The other type is an American date format, i.e. m/dd/yyyy
(5/25/1995).
> So the variable looks like:

Use

. di date("5/25/1995", "mdy")
12928

Nick
n.j.cox@durham.ac.uk

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